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Firlakuza [10]
3 years ago
9

What did sewage treatment in Ancient Rome and 19th century London have in common?

Chemistry
1 answer:
dolphi86 [110]3 years ago
5 0

Answer:

The history of water supply and sanitation is one of a logistical challenge to provide clean water and sanitation systems since the dawn of civilization. Where water resources, infrastructure or sanitation systems were insufficient, diseases spread and people fell sick or died prematurely.

Explanation:

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You are cooking dinner using a metal pan. When you pick up the pan,the handle burns your hand. Which form of thermal energry tra
VLD [36.1K]

Answer:

Conduction

Explanation:

4 0
2 years ago
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I need some advice, I know like this is random, and I can not do this cuz issa place for questions about school work and stuff,
alina1380 [7]

Answer:

well try talking to him first and being his friend. introduce yourself and try not to be too awkward or shy. can't reltate lol. after that if he really likes you, he'll initiate stuffs ^^

Explanation:

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3 years ago
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It takes 60 mL of 0.20 M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (H2CO3) for the following chemical reac
irina1246 [14]

If It takes 60mL of 0.20M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (H_2CO_3), then the concentration of the carbonic acid is 0.24M

The reaction between NaOH solution and H_2CO_3 is written below

2NaOH + H_2CO_3 \rightarrow Na_2CO_3 + 2H_2O

Volume of NaOH, V_B = 60 ml

Volume of H_2CO_3, V_A=25 ml

Molarity of H_2CO_3, C_A=?

Molarity of NaOH, C_B=0.20M

Number of moles of H_2CO_3, n_A=1

Number of moles of NaOH, n_B=2

The mathematical equation for neutralization reaction is:

\frac{C_AV_A}{C_BV_B} =\frac{n_A}{n_B}

Substitute  C_B=0.2 M,  n_A=1,  n_B=2,  V_B = 60ml, and  V_A=25 ml into the equation above in order to solve for C_A

\frac{C_A \times 25}{0.2 \times 60}=\frac{1}{2}  \\\\50C_A=12\\\\C_B=\frac{12}{50} \\\\C_B=0.24M

Therefore, the concentration of the carbonic acid is 0.24M

Learn more here: brainly.com/question/25943090

3 0
2 years ago
Consider the ions of potassium (K) and sulfur (S), Write chemical formulas for all possible ionic compounds involving these ions
attashe74 [19]

The compounds that could exists between the ions K^+ and S^2- are K2S and K2S2.

<h3>What is an ionic compound?</h3>

An ionic compound is a commpound that is composed of ions. Let us note that ionic compounds are always such that the sum of the charges on the ions is zero.

Hence, the compounds that could exists between the ions K^+ and S^2- are K2S and K2S2.

Learn more about ionic compounds:brainly.com/question/9167977

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2 years ago
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Choose the correct net ionic equation for the reaction (if a reaction occurs) between CaCl2 and AgNO3: Group of answer choices
Levart [38]

Answer:

2Ag⁺(aq) + 2Cl⁻(aq) -> 2AgCl(s)

Explanation:

Silver nitrate and calcium chloride will react in a double displacement reaction (which has to produce a precipitate, a gas, or water to have a reaction).

This reaction will produce a silver chloride precipitate and a solution of calcium nitrate.

The reaction will be 2AgNO3(aq) + CaCl2(aq) -> 2AgCl(s) + Ca(NO3)2(aq)

To write a net ionic equation:

1. Write the balanced molecular equation.

   2AgNO3 + CaCl2 -> 2AgCl(ppt) + Ca(NO3)2

2. Write the balanced complete ionic equation.

To write the complete ionic equation:

- Start with a balanced molecular equation.

2AgNO3(aq) + CaCl2(aq) -> 2AgCl(s) + Ca(NO3)2(aq)

- Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions

       indicate the correct formula and charge of each ion

       indicate the correct number of each ion

       write (aq) after each ion

- Bring down all compounds with (s), (l), or (g) unchanged.

2Ag⁺(aq) + 2NO³⁻(aq) + Ca²⁺(aq) + 2Cl⁻(aq) -> 2AgCl(s) + Ca²⁺(aq) + 2NO³⁻(aq)

3. Cross out the spectator ions that are present. Spectator ions are ions that are present in the reaction mixture but do not participate in it. You can recognize spectator ions by looking for ions that are present on both sides of the equation.

4. Write the "leftovers" as the net ionic equation.

2Ag⁺(aq) + 2Cl⁻(aq) -> 2AgCl(s)

4 0
3 years ago
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