Step 1:
Start by setting it up with the divisor 8 on the left side and the dividend 27 on the right side like this:
8 ⟌ 2 7
Step 2:
The divisor (8) goes into the first digit of the dividend (2), 0 time(s). Therefore, put 0 on top:
0
8 ⟌ 2 7
Step 3:
Multiply the divisor by the result in the previous step (8 x 0 = 0) and write that answer below the dividend.
0
8 ⟌ 2 7
0
Step 4:
Subtract the result in the previous step from the first digit of the dividend (2 - 0 = 2) and write the answer below.
0
8 ⟌ 2 7
- 0
2
Step 5:
Move down the 2nd digit of the dividend (7) like this:
0
8 ⟌ 2 7
- 0
2 7
Step 6:
The divisor (8) goes into the bottom number (27), 3 time(s). Therefore, put 3 on top:
0 3
8 ⟌ 2 7
- 0
2 7
Step 7:
Multiply the divisor by the result in the previous step (8 x 3 = 24) and write that answer at the bottom:
0 3
8 ⟌ 2 7
- 0
2 7
2 4
Step 8:
Subtract the result in the previous step from the number written above it. (27 - 24 = 3) and write the answer at the bottom.
0 3
8 ⟌ 2 7
- 0
2 7
- 2 4
3
You are done, because there are no more digits to move down from the dividend.
The answer is the top number and the remainder is the bottom number.
Therefore, the answer to 27 divided by 8 calculated using Long Division is:
3
Answer:
The volume up to cylindrical portion is approx 32355 liters.
Explanation:
The tank is shown in the attached figure below
The volume of the whole tank is is sum of the following volumes
1) Hemisphere top
Volume of hemispherical top of radius 'r' is

2) Cylindrical Middle section
Volume of cylindrical middle portion of radius 'r' and height 'h'

3) Conical bottom
Volume of conical bottom of radius'r' and angle
is

Applying the given values we obtain the volume of the container up to cylinder is
Hence the capacity in liters is 
Answer:
6 m²
Explanation:
application of fluid pressure according to Pascal's principle for the two pistons is given as:

Where P₁ is the pressure at the input and P₂ is the pressure at the output.
But P₁ = F₁ / A₁ and P₂ = F₂ / A₂
Where F₁ and F₂ are the forces applied at the input and output respectively and A₁ and A₂ are the area of the input pipe and output pipe respectively
Since, 

But A₁ = 0.2 m², F₁ = 250 N, F₂ = 7500 N. Substituting values to get:

Therefore, the area of the pipe below the load is 6 m²
I would go with C but i am not 100 percent on that
Answer:
Number of rollers required to complete the compaction are 2
Explanation:
The solution is given in the attachments.