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3 years ago

Match the scenario to the problem-solving step it represents.

Engineering

1 answer:

Nataliya [291]3 years ago

7 0

Answer:

1. Establish goals.

2. Generate solutions.

3. Implement solutions.

Explanation:

The problem-solving process can be defined as the systematic approach used to identify and determine the solution to a particular problem.

The steps involved in the problem-solving process are;

1. Identify and define the problem: this is the first step to be taken in solving a problem. This is to ensure that, the focus is on the main issue or situation (goal) and all efforts is channeled in the right direction rather than the symptoms.

2. Gathering of information: this helps to consider the options available in solving a problem effectively.

3. Consider your options: this helps to compare the available and viable solutions to the problem.

4. Weigh disadvantages and evaluate a solution: you weigh the disadvantages of each solution, before choosing the one with the least disadvantages.

In this scenario, the problem-solving steps are appropriately and accurately matched with the a real-life problem below;

Establish goals: Karen wants to graduate with an accounting degree to become a budget analyst. She has identified and established her goal, which is to obtain an accounting degree so as to become a budget analyst.
Generate solutions: Karen researches accounting programs at various universities. Next, she made a research on possible solutions to help her achieve her goals.
Implement solutions: Karen enrolls in a nationally accredited business school at a university. Finally, she settles with the best solution with respect to obtaining an accounting degree and a business analyst in the long-run.

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Koch traded Machine 1 for Machine 2 when the fair market value of both machines was $60,000. Koch originally purchased Machine 1

Mariana [72]

Answer:

Koch's adjusted basis in machine 2 after the exchange is $60,000

Explanation:

given data

fair market value = $60,000

originally purchased Machine 1 = $76,900

Machine 1 adjusted basis = $40,950

Machine 2 seller purchase = $64,050

Machine 2 adjusted basis = $55,950

solution

As he exchanged machine for another at $60,000

and this exchanged in fair market

so adjusted basis = $50,000

Adjusted basis is the price of the item that affects the factors that are considered price. These factors usually include taxes, depreciation value, and other costs of acquiring and maintaining a given item. Adjusted basis is important so the right amount to sell

Adjusted basis increases when a person deducts expenses from factor taxes and operating statements

so Koch's adjusted basis in machine 2 after the exchange is $60,000

3 0

3 years ago

Select the correct answer.

boyakko [2]

I think the answer is b

6 0

3 years ago

Read 2 more answers

What is the Energy of moving things? mechanical sound nuclear Light

Elenna [48]

Answer: Kinetic energy

Explanation: If you live in a country other than UK you will probably call it something different

4 0

3 years ago

Read 2 more answers

Think about a packed lunch and the

Mazyrski [523]

Answer:

They are combination structures made up of solid, and shell structures.

Explanation:

Thinking of a lunch pack which is shaped as a solid bag made up of different compartments to hold food, what comes to mind are;

1. The solid structure: This is seen in the form of the bag which has solid makeup.

2. The shell structure: This is seen in the different compartments holding the different types of foods. Shell structures are usually in the form of containers made to hold something in.

4 0

3 years ago

A hot air balloon is used as an air-vehicle to carry passengers. It is assumed that this balloon is sealed and has a spherical s

monitta

Answer:

a. $\dfrac{D_{1}}{ D_{2}} = \left (\dfrac{ \left{D_1} }{ {D_2}} \right )^{-3\times n}$ which is constant therefore, n = constant

b. The temperature at the end of the process is 109.6°C

c. The work done by the balloon boundaries = 10.81 MJ

The work done on the surrounding atmospheric air = 10.6 MJ

Explanation:

p₁ = 100 kPa

T₁ = 27°C

D₁ = 10 m

v₂ = 1.2 × v₁

p ∝ α·D

α = Constant

$v_1 = \dfrac{4}{3} \times \pi \times r^3$

$\therefore v_1 = \dfrac{4}{3} \times \pi \times \left (\dfrac{10}{2} \right )^3 = 523.6 \ m^3$

v₂ = 1.2 × v₁ = 1.2 × 523.6 = 628.32 m³

Therefore, D₂ = 10.63 m

We check the following relation for a polytropic process;

$\dfrac{p_{1}}{p_{2}} = \left (\dfrac{V_{2}}{V_{1}} \right )^{n} = \left (\dfrac{T_{1}}{T_{2}} \right )^{\dfrac{n}{n-1}}$

We have;

$\dfrac{\alpha \times D_{1}}{\alpha \times D_{2}} = \left (\dfrac{ \dfrac{4}{3} \times \pi \times \left (\dfrac{D_2}{2} \right )^3}{\dfrac{4}{3} \times \pi \times \left (\dfrac{D_1}{2} \right )^3} \right )^{n} = \left (\dfrac{ \left{D_2} ^3}{ {D_1}^3} \right )^{n}$

$\dfrac{D_{1}}{ D_{2}} = \left (\dfrac{ \left{D_2} }{ {D_1}} \right )^{3\times n} = \left (\dfrac{ \left{D_1} }{ {D_2}} \right )^{-3\times n}$

$\dfrac{ D_{1}}{ D_{2}} = \left ( 1.2 \right )^{n} = \left (\dfrac{ \left{D_2} ^3}{ {D_1}^3} \right )^{n}$

$log \left (\dfrac{D_{1}}{ D_{2}}\right ) = -3\times n \times log\left (\dfrac{ \left{D_1} }{ {D_2}} \right )$

n = -1/3

Therefore, the relation, pVⁿ = Constant

b. The temperature T₂ is found as follows;

$\left (\dfrac{628.32 }{523.6} \right )^{-\dfrac{1}{3} } = \left (\dfrac{300.15}{T_{2}} \right )^{\dfrac{-\dfrac{1}{3}}{-\dfrac{1}{3}-1}} = \left (\dfrac{300.15}{T_{2}} \right )^{\dfrac{1}{4}}$