Most minerals can be characterized and classified by their unique physical properties: hardness, luster, color, streak, specific gravity, cleavage, fracture, and tenacity.
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Answer:
Please check explanation for answer
Explanation:
Here, we are concerned with stating the advantages and disadvantages of using a 6 tube passes instead of a 2 tube passes of the same diameter:
<u>Advantages</u>
* By using a 6 tube passes diameter, we are increasing the surface area of the heat transfer surface
* As a result of increasing the heat transfer surface area, the rate of heat transfer automatically increases too
Thus, from the above, we can conclude that the heat transfer rate of a 6 tube passes is higher than that of a 2 tube passes of the same diameter.
<u>Disadvantages</u>
* They are larger in size and in weight when compared to a 2 tube passes of the same diameter and therefore does not find use in applications where space conservation is quite necessary.
* They are more expensive than the 2 tube passes of the same diameter and thus are primarily undesirable in terms of manufacturing costs
Answer:
Explanation:
In the diagram there three gears in which gear 1 is input gear ,gear 2 is idle gear and gear 3 is out put gear.
Lets take
All external matting gears will rotates in opposite direction with respect to each other.
So the speed of gear third can be given as follows
To solve the problem it is necessary to use the concepts related to frictional dissipation per unit mass, energy balance equation and Volumetric flow rate.
The frictional dissipation per unit mass is defined as
Where,
Superficial velocity of fluid
Fluid viscoisty
Porosity
Fluid density
L = Packed bed length
= Effective particle diameter
Through energy balance equation we have that
Neglect the change in velocity and pressure and the work done we have,
We have also that de grade is defined as
With our values and replacing at the previous equation we have,
Previously with the given depth and height we have to
Therefore the Volumetric flow rate,
Therefore the desired volumetric flow rate is 2456gal/min
Answer:
The stiffness of an axially loaded bar is (EA)/L
The flexibility of an axially loaded bar is L/(EA)
The stiffness of a torsionally loaded round bar is (GJ)/L
The flexibility of a torsionally loaded round bar is L/(GJ)
Explanation:
For axially loaded round bar, ExA measures, what is known as, the axial rigidity of the round bar. "E" is defined as the Young's modulus which is the property of the bar that measures the stiffness of the bar itself and is meausred in Pascals. A is the area of the cross section of the bar. L is the entire length of the bar. Multiple the Young's modulus with the cross sectional area and divide the value by the length which will give the stiffness of the axially loaded bar. The inverse of this equation will give you the flexibility.
For a Torsionally loaded round bar, the formula is a bit different. G is the modulus rigidity of the bar and J is the Torsional constant. GJ is calculated by multiplying the applied torque with the length od the bar and dividing the result by the angle of the twist. Dividing the result by the length will give the stiffness. Inverse of the equation measuring stiffness gives the flexibility