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Serggg [28]
3 years ago
6

How far is it between the cafeteria and the swimming pool

Physics
1 answer:
NARA [144]3 years ago
5 0
C distance

Explanation:
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A moving billiard ball hits another ball at rest, causing the first ball to stop moving as the second rolls away. If the two bal
mario62 [17]
<span>The momentum of the second ball will depend on the acceleration of the first moving ball.</span>
3 0
3 years ago
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The number of revolutions of two pulleys is inversely proportional to their diameters. If a 24-inch diameter pulley making 400 r
Fed [463]

Answer:

C) 1200 rpm

Explanation:

D_1 = Diameter of bigger pulley = 24 inch

D_2 = Diameter of smaller pulley = 8 inch

N_1 = Speed of bigger pulley = 400 rpm

N_2 = Speed of smaller pulley

The relation between revolutions per minute and diameter is that they are inversely proportional.

\frac{N_1}{N_2}=\frac{D_2}{D_1}\\\Rightarrow \frac{400}{N_2}=\frac{8}{24}\\\Rightarrow N_2=\frac{24\times 400}{8}\\\Rightarrow N_2=1200\ rpm

The number of revolutions per minute of the smaller pulley is 1200 rpm

7 0
3 years ago
Group one on the periodic table shares which characteristics.?
Dmitry_Shevchenko [17]
Group one on the periodic table, also known as the alkali metals, all:
- form ions with a charge of +1
- display similar extreme chemical behaviour
- have typical metallic properties
- are far too reactive to be found naturally in their pure forms
4 0
3 years ago
A disk between vertebrae in the spine is subjected to a shearing force of 425 N. Find its shear deformation, taking it to have a
zzz [600]

Answer:

option A

Explanation:

given,

shear force = 425 N

Shear modulus = 1.7 × 10⁹ N/m²

disk equivalent to solid cylinder

height = 0.7 cm  and diameter = 6.50 cm

\delta = \dfrac{VL}{AG}\\\\\delta = \dfrac{425\times 0.007}{0.25 \times \pi d^2\times 1.7\times 10^9}\\\\\delta = \dfrac{425\times 0.007}{0.25 \times \pi\times 0.065^2\times 1.7\times 10^9}\\\\\delta  = 5.27 \times 10^{-7} m

hence, the correct answer is option A

3 0
4 years ago
To measure the coefficient of kinetic friction by sliding a block down an inclined plane the block must be in equilibrium.
lozanna [386]

Answer:

a)

Explanation:

  • A block sliding down an inclined plane, is subject to two external forces along the slide.
  • One is the component of gravity (the weight) parallel to the incline.
  • If the inclined plane makes an angle θ with the horizontal, this component (projection of the downward gravity along the incline, can be written as follows:

        F_{gp} = m*g* sin \theta (1)

       (taking as positive the direction of the movement of the block)

  • The other force, is the friction force, that adopts any value needed to meet the Newton's 2nd Law.
  • When θ is so large, than the block moves downward along the incline, the friction force can be expressed as follows:

       F_{f} = \mu_{k} * N  (2)

  • The normal force, adopts the value needed to prevent any vertical movement through the surface of the incline:

       N = m*g* cos \theta (3)

  • In equilibrium, both forces, as defined in (1), (2) and (3) must be equal in magnitude, as follows:

        m*g* sin \theta =  \mu_{k} * m*g* cos \theta

  • As the block is moving, if the net force is 0, according to Newton's 2nd Law, the block must be moving at constant speed.
  • In this condition, the friction coefficient is the kinetic one (μk), which can be calculated as follows:

        \mu_{k}  = tg \theta

8 0
3 years ago
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