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Alenkasestr [34]
3 years ago
10

Chemistry Help (Naming Oxyacids Chart)

Chemistry
1 answer:
guapka [62]3 years ago
7 0

Answer:

HClO₃ /chloric acid /suffix -ic/ ClO₃⁻ (chlorate)

HClO₂/ chlorous acid/ suffix -ous/ ClO₂⁻ (chlorite)

HNO₃ /nitric acid /suffix -ic/ NO₃⁻ (nitrate)

HNO₂/ nitrous acid/ suffix -ous/ NO₂⁻ (nitrite)

Explanation:

Chlorine has 4 positive oxidation numbers to form oxyacids: +1, +3, +5 and +7.

  • When it uses the oxidation number +5, it forms HClO₃, which is named chloric acid, with the suffix -ic. When it loses an H⁺, it forms the oxyanion ClO₃⁻ (chlorate).
  • When it uses the oxidation number +3, it forms HClO₂, which is named chlorous acid, with the suffix -ous. When it loses an H⁺, it forms the oxyanion ClO₂⁻ (chlorite).

Nitrogen has 2 positive oxidation numbers to form oxyacids: +3 and +5.

  • When it uses the oxidation number +5, it forms HNO₃, which is named nitric acid, with the suffix -ic. When it loses an H⁺, it forms the oxyanion NO₃⁻ (nitrate).
  • When it uses the oxidation number +3, it forms HNO₂, which is named nitrous acid, with the suffix -ous. When it loses an H⁺, it forms the oxyanion NO₂⁻ (nitrite).
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When combing one's hair, the comb becomes positively charged. What happens to the hair being combed?
TEA [102]

Since the comb is positively charged, the hair will stick to the comb.

I think

6 0
4 years ago
A solution contains 0.25 M Ni(NO3)2 and 0.25 M Cu(NO3)2. Can the metal ions be separated by slowly adding Na2CO3? Assume that fo
amid [387]

Explanation:

Ksp of NiCO3 = 1.4 x 10^-7

Ksp of CuCO3 = 2.5 x 10^-10

Ionic equations:

NiCO3 --> Ni2+ + CO3^2-

CuCO3 --> Cu2+ + CO3^2-

[Cu2+][CO3^2-]/[Ni2+][CO3^2-]

= (2.5* 10^-10)/(1.4* 10^-7)

= 0.00179.

[Cu2+]/[Ni2+]

= 0.00179

= 0.00179*[Ni2+]

If all of Cu2+ is precipitated before Na2CO3 is added.

= 0.00179 * (0.25)

The amount of Cu2+ not precipitated = 0.000448 M

The percent of Cu2+ precipitated before the NiCO3 precipitates = concentration of Cu2+ unprecipitated/initial concentration of Cu2+ * 100

= 0.000448/0.25 * 100

= 0.18%

Therefore, percentage precipitated = 100 - 0.18

= 99.8%

The two metal ions can be separated by slowly adding Na2CO3. Thus that is the unpptd Cu2+.

8 0
3 years ago
Write the balanced equation for the reaction given below: C2H6 + O2 --> CO2 + H2O. If 16.4 L of C2H6 reacts with 0.980 mol of
Natalka [10]
The balanced reaction: C2H6 + 7/2 O2 -> 2 CO2 + 3 H2O

We first convert volume of C2H6 to no. of moles. We use the conditions at STP where 1 mol = 22.4 L thus,

Moles C2H6 = 16.4 L/ 22.4 L =0.7321 mol

In order to determine the limiting reagent, we look at the given amounts of the reactants.

0.7321 mol C2H6 (7/2 mol O2 / 1 mol C2H6) = 2.562 mol O2

From the given amounts of the reactants, we can say that O2 is the limiting reactant since we need 2.562 mol O2 to completely react the given amount of C2H6. The excess reagent is C2H6

To calculate for the amount of products and excess reactants:

0.980 mol O2 (2 mol CO2 / (7/2 mol O2)) = 0.56 mol CO2 (22.4 L / 1 mol ) =12.544 L CO2
<span>0.980 mol O2 (1 mol C2H6 / (7/2 mol O2)) = 0.28 mol C2H6
Excess C2H6 = 0.7321 mol - 0.28 mol C2H6 = 0.4521 mol C2H6

We then use the molecular weight of C2H6 to convert the excess amount to grams.

0.4521 mol C2H6 (30.08 g C2H6 / 1 mol C2H6) = <span>13.60 g C2H6 
</span></span>
<span>Since the limiting reagent is O2 there will be no oxygen atoms that will be left after the reaction.</span>
5 0
3 years ago
Planck's constant, h, is 6.626 x 10-34 Js. The speed of light in a vacuum, c, is 3.00 x 108 m/s. Calculate the energy of ultravi
igomit [66]

Given the Planck's constant and the speed of light, the energy of the ultraviolet light with a frequency of 9.58×10¹⁴ Hz is 6.35×10¯¹⁹ J (Option C)

<h3>Data obtained from the question </h3>
  • Planck's constant (h) = 6.626×10¯³⁴ Js
  • Speed of light (v) = 3×10⁸ m/s
  • Frequency (f) = 9.58×10¹⁴ Hz
  • Energy (E) =?

<h3>How to determine the energy </h3>

The energy of the ultraviolet light can be obtained as follow:

E = hf

E = 6.626×10¯³⁴ × 9.58×10¹⁴

E = 6.35×10¯¹⁹ J

Learn more about energy:

brainly.com/question/10703928

8 0
2 years ago
I need help with this question ASAP this should have 2 answers
murzikaleks [220]

Answer:

The correct answer is B. and C. according to me!

8 0
3 years ago
Read 2 more answers
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