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2 years ago

Chemistry Help (Naming Oxyacids Chart)

Chemistry

1 answer:

guapka [62]2 years ago

7 0

Answer:

HClO₃ /chloric acid /suffix -ic/ ClO₃⁻ (chlorate)

HClO₂/ chlorous acid/ suffix -ous/ ClO₂⁻ (chlorite)

HNO₃ /nitric acid /suffix -ic/ NO₃⁻ (nitrate)

HNO₂/ nitrous acid/ suffix -ous/ NO₂⁻ (nitrite)

Explanation:

Chlorine has 4 positive oxidation numbers to form oxyacids: +1, +3, +5 and +7.

When it uses the oxidation number +5, it forms HClO₃, which is named chloric acid, with the suffix -ic. When it loses an H⁺, it forms the oxyanion ClO₃⁻ (chlorate).

When it uses the oxidation number +3, it forms HClO₂, which is named chlorous acid, with the suffix -ous. When it loses an H⁺, it forms the oxyanion ClO₂⁻ (chlorite).

Nitrogen has 2 positive oxidation numbers to form oxyacids: +3 and +5.

When it uses the oxidation number +5, it forms HNO₃, which is named nitric acid, with the suffix -ic. When it loses an H⁺, it forms the oxyanion NO₃⁻ (nitrate).

When it uses the oxidation number +3, it forms HNO₂, which is named nitrous acid, with the suffix -ous. When it loses an H⁺, it forms the oxyanion NO₂⁻ (nitrite).

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Answer:

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3 years ago

You have 54.32 grams of PbCl4. How many moles of PbCl4 do you have?

Dima020 [189]

Answer:

0.156mol

Explanation:

Number of moles of a substance can be calculated from its mass by dividing its mass by molar mass i.e.

Number of moles (n) = mass/molar mass

Molar mass of PbCl4 is as follows, where Pb = 207.2g/mol, Cl = 35.5g/lol

PbCl4 = 207.2 + 35.5(4)

= 207.2 + 142

= 349.2g/mol

Using: mole = mass/molar mass

mole = 54.32 grams ÷ 349.2g/mol

mole = 0.1555

mole = 0.156mol

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2 years ago

What disease is spread through warm climates ?

galina1969 [7]

Answer:

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Explanation:

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3 years ago

the solubility product Ag3PO4 is: Ksp = 2.8 x 10^-18. What is the solubility of Ag3PO4 in water, in moles per liter?

guapka [62]

Answer : The solubility of $Ag_3PO_4$ in water is, $1.8\times 10^{-5}mol/L$

Explanation :

The solubility equilibrium reaction will be:

$Ag_3PO_4\rightleftharpoons 3Ag^++PO_4^{3-}$

Let the molar solubility be 's'.

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ag^{+}]^3[PO_4^{3-}]$

$K_{sp}=(3s)^3\times (s)$

$K_{sp}=27s^4$

Given:

$K_{sp}$ = $2.8\times 10^{-18}$

Now put all the given values in the above expression, we get:

$K_{sp}=27s^4$

$2.8\times 10^{-18}=27s^4$

$s=1.8\times 10^{-5}M=1.8\times 10^{-5}mol/L$

Therefore, the solubility of $Ag_3PO_4$ in water is, $1.8\times 10^{-5}mol/L$

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3 years ago

Why is it necessary to adjust the height of the graduated cylinder when measuring the volume of CO2 (g) produced? What type of e

kolezko [41]

Explanation:

This process ensures that the pressure inside of the graduated cylinder is the same as the atmospheric pressure in the room.

Suppose the level of water inside and outside the cylinder is same, pressure stays the same. Therefore, total pressure of the is made equal to atmospheric pressure by adjusting the height of cylinder. it is done till the water level is equal.

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3 years ago