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muminat
3 years ago
15

A student burned 0.250 g of magnesium metal in an open crucible.Oxygen from the air combined with the metal forming magnesium ox

ide. If 0.421 g of magnesium oxide were produced, what mass of oxygen combined with the metal? 1. 0.171 g 2. 0.671 g 3. 1.684 g 4. 0.594 g
Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Answer:

0.171 grams of oxygen combined with the metal.

Explanation:

2Mg+O_2\rightarrow 2MgO

Mass of magnesium oxide produced = 0.421 g

Mass of magnesium metal used = 0.250 g

Suppose reaction completely converts the magnesium into magnesium oxide.

Mass of oxygen combined with magnesium = m

0.421 g = 0.250 g + m

m =  0.421 g - 0.250 g = 0.171 g

0.171 grams of oxygen combined with the metal.

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Yes the answer is a , kinetic energy
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Write a balanced net ionic equation for the following reaction: SrCl2(aq) + H2CO3(aq) → SrCO3(s) + HCl (aq)
max2010maxim [7]
  We will balance the equation in the following order: metals, amethals, carbon, hydrogen and oxygen (the most common order).
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SrCl_2_{(aq)}+H_2CO_3_{(aq)}\to SrCO_3_{(s)}+2HCl_{(aq)}
 
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SrCl_2_{(aq)}+H_2CO_3_{(aq)}\to SrCO_3_{(s)}+2HCl_{(aq)}
5 0
2 years ago
The dissolution of 0.200 l of sulfur dioxide at 19 °c and 745 mmhg in water yields 500.0 ml of aqueous sulfurous acid. The solut
aivan3 [116]

Answer:

Molarity=1.22\ M

Explanation:

Given:  

Pressure = 745 mm Hg

Also, P (mm Hg) = P (atm) / 760

Pressure = 745 / 760 = 0.9803 atm

Temperature = 19 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (19 + 273.15) K = 292.15 K  

Volume = 0.200 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9803 atm × 0.200 L = n × 0.0821 L.atm/K.mol × 292.15 K  

⇒n = 0.008174 moles

From the reaction shown below:-

H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O

1 mole of H_2SO_4 react with 2 moles of NaOH

0.008174 mole of H_2SO_4 react with 2*0.008174 moles of NaOH

Moles of NaOH = 0.016348 moles

Volume = 13.4 mL = 0.0134 L ( 1 mL = 0.001 L)

So,

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.016348}{0.0134}\ M

Molarity=1.22\ M

8 0
3 years ago
Which element has the lowest first ionization energy? (F), (Li), (Fr), (Rb)?
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6 0
3 years ago
Predict the sign of the entropy change,Delta S, for each of the following reactions:The signs are either going to be pos or nega
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d) P_4(g)+5O_2(g)\rightarrow P_4O_{10}(s) : negative

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f) I_2(s)\rightarrow I_2(g) : positive.

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from  an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

\Delta S is positive when randomness increases and \Delta S is negative when randomness decreases.

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As ions are moving to solid form , randomness decreases and thus sign of \Delta S is negative.

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c) 2NH_3(g)\rightarrow N_2(g)+3H_2(g)

As 2 moles of reactants are converted to 4 moles of products , randomness increases and thus sign of \Delta S is positive.

d) P_4(g)+5O_2(g)\rightarrow P_4O_{10}(s)

As gas is changing to solid, randomness decreases and thus sign of \Delta S is negative.

e) C_4H_8(g)+6O_2(g)\rightarrow 4CO_2(g)+4H_2O(g)

As 7 moles of reactants are converted to 8 moles of products , randomness increases and thus sign of \Delta S is positive.

f) I_2(s)\rightarrow I_2(g)

As solid is changing to gas, randomness increases and thus sign of \Delta S is positive.

6 0
3 years ago
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