Answer: The molar solubility of barium fluoride is 0.0183 moles/liter.
Explanation:
The equation for the reaction will be as follows:
By Stoichiometry,
1 mole of 
gives 2 moles of 
and 1 mole of 
Thus if solubility of is s moles/liter, solubility of is s moles/liter and solubility of is 2s moles/liter
Therefore,
![K_sp=[Ba^{2+}][F^{-}]^2](https://tex.z-dn.net/?f=K_sp%3D%5BBa%5E%7B2%2B%7D%5D%5BF%5E%7B-%7D%5D%5E2)
![2.45\times 10^{-5}=[s][2s]^2](https://tex.z-dn.net/?f=2.45%5Ctimes%2010%5E%7B-5%7D%3D%5Bs%5D%5B2s%5D%5E2)
Thus the molar solubility of barium fluoride is 0.0183 moles/liter.
Answer:
Mass = 4.44 g
Explanation:
Given data:
Number of moles of Ne = 0.220 mol
Mass in gram = ?
Solution:
Formula:
Number of moles = mass/ molar mass
Molar mass of Ne = 20.2 g/mol
by putting values,
0.220 mol = mass/ 20.2 g/mol
Mass = 0.220 mol × 20.2 g/mol
Mass = 4.44 g
Element 6 has the lowest ionization energy
The starting substances in a chemical reaction are called reactants - they are written on the left side of a chemical equation.
Answer:
D
Explanation:
Scientists measure a variety of properties to determine water quality. These include temperature, acidity (pH), dissolved solids (specific conductance), particulate matter (turbidity), dissolved oxygen, hardness and suspended sediment.
