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Alexandra [31]
3 years ago
11

How many miles will a person run an 800 km race?

Chemistry
1 answer:
dolphi86 [110]3 years ago
7 0

Answer:

uhh its 497 miles

Explanation:

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Which statements about moon phases In a lunar month are true?
saveliy_v [14]

Answer:

1. The same pattern of phases repeats monthly

2. Waxing moon phases are visible between the new and full moon

6. A full moon appears toward the middle of a lunar month

Explanation:

Moon has eight phases which is used by the ancient people for the identification of date of the month. Phases of moon tells us about the starting, middle and end of the month. At the starting of the month, waxing crescent appears while at the middle of the month, the moon gains its full shape. Phases which occurs between new and full moon is known as waxing.

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3 years ago
Why is carbon dioxide used in fire extinguisher?
rjkz [21]
As Fire needs oxygen to burn, Carbon Dioxide Covers the fire like an blanket and cuts the contact of fire to the oxygen present in the air, So Fire stops burning.That is why Carbon Dioxide is Considere as the best Fire Extinguisher.
3 0
3 years ago
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Whichof the following is another name for science
snow_lady [41]
Field or discipline
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8 0
3 years ago
Calculate the number of hydrogen atoms present in 40g of urea, (NH2)2CO
tekilochka [14]

Answer: There are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

Explanation:

Given: Mass of urea = 40 g

Number of moles is the mass of substance divided by its molar mass.

First, moles of urea (molar mass = 60 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

So, the number of atoms present in 0.67 moles are as follows.

0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms

In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.

4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms

Thus, we can conclude that there are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

7 0
3 years ago
Which of the following are directly proportional? *
Ivanshal [37]
Volume and temperature.
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3 years ago
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