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sdas [7]
3 years ago
13

A chemist added an excess of sodium sulfate to a solution of a soluble barium compound to precipitate all of the barium ions as

barium sulfate, BaSO4. How many grams of barium ions are in a 441-mg sample of the barium compound if a solution of the sample gave 403 mg BaSO4 precipitate? What is the mass percentage of barium compound?
Chemistry
1 answer:
grigory [225]3 years ago
8 0

Answer:

  259.497 mg,   58.84%

Explanation:

BaSO₄ → Ba²⁺ + SO₄²⁻

to calculate the mole of BaSO₄

mole BaSO₄ = mass given / molar mass = 403 mg / 233.38 g/mol = 1.7268 mol

comparing the mole ratio

1.7268 mol of BaSO₄ yields 1.7268 mol of Ba²⁺

403 mg BaSO₄  yields     ( 1.7268 × 137.327 ) where 137.327 is the molar mass of Barium mol of Ba²⁺

441 mg BaSO₄  will yield   ( 1.7268 × 137.327  × 441 mg ) / 403 mg = 259 .497 mg

mas percentage of the Barium compound = 259 .497 mg / 441 mg × 100 = 58.84%

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The energy of the universe is constant. That what mentioned by the first law of thermodynamics,
Goryan [66]

Answer:

No, ΔE does not always equal zero because it refers to the systems internal energy, which is affected by heat and work

Explanation:

According to the first law of thermodynamics, energy is neither created nor destroyed. This implies that the total energy of a system is always a constant.

So, according to the first law of thermodynamics we have that ΔE = q + w. This means that the value of  ΔE depends on q (heat) and  w(work). Hence ΔE is not always zero since it depends on the respective values of q and w.

5 0
3 years ago
A chef makes a marinade by mixing red pepper flakes, dried onion flakes, and a ground ginger with soy sauce. He sets the marinad
Alisiya [41]

Answer:

Suspension

Explanation:

This mixture is a simple suspension.

A suspension is a mixture of small insoluble particles of a solid in a liquid or gas. Here, it is insoluble particles in liquid.

  • Suspensions are settle on standing this is why they have to be mixed again.
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3 0
3 years ago
Read 2 more answers
What is the molar mass of 4.23 g of an elemental gas in a 2.5L container at 282K and 1.4 atm?
balu736 [363]

Answer:

27.98g/mol

Explanation:

Using ideal gas law equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

T = temperature (K)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

According to the information given:

V = 2.5L

P = 1.4 atm

T = 282K

n = ?

Using PV = nRT

n = PV/RT

n = 1.4 × 2.5/0.0821 × 282

n = 3.5/23.1522

n = 0.151mol

Using the formula to calculate molar mass of the elemental gas:

mole = mass/molar mass

Molar mass = mass/mole

Molar mass = 4.23g ÷ 0.151mol

Molar mass = 27.98g/mol

6 0
3 years ago
When 1mol of a gas burns at constant pressure, it produces 2430 j of heat and does 5 kj of work?
navik [9.2K]
Convert  2430j  to  Kj  that  is  divide  by  1000 
2430/1000=2.430
delta  E  =Q+W
q is  the  heat  done  
w is  the  work done and  since  is work  is  done is by  the  system therefore  it  is  negative
w  is  therefore -5kj
q=-2.430
delta E =-2.430 + -5= -7.43kj/mol

7 0
3 years ago
How many electrons, protons, and neutrons does Lithium have?
Andrej [43]
Lithium,
Electrons are 3
Protons are 3
Neutrons are 4
4 0
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