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Anestetic [448]
3 years ago
5

Changing the speed of a synchronous generator changes A) the frequency and amplitude of the output voltage. B) only the frequenc

y of the output voltage. C) only the amplitude of the output voltage. D) only the phase of the output voltage.
Physics
1 answer:
Dmitrij [34]3 years ago
8 0

Answer:

A) the frequency and amplitude of the output voltag

Explanation:

Changing the speed of a synchronous generator changes both the output voltage (amplitude of the wave) and frequency as they tend to increase.

Changing the speed regulator will change the engine throttle setting to maintain the speed.

While the power, torque, current, fuel flow rate and torque angle will have decreased.

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Explica de que tipo es cada oración según la actitud del hablante
Volgvan

Answer:

Según la actitud del hablante las oraciones se clasifican en enunciativas, interrogativas, etc. ... adverbios o expresiones que complementan a toda la oración (COr): ojalá, quizá.

Explanation:

7 0
2 years ago
It is possible a tree could fall down, even if no one did anything to it. A. True B. False
hichkok12 [17]

Answer:

This is TRUE

Explanation:

The tree can fall down even though no one did anything to it...

A hard breeze can blow and it can fall down or something else can cause it to topple...

Not only humans can make trees topple over...

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8 0
3 years ago
What type of energy transformation occurs when a light bulb is turned on?
Vikentia [17]
Electical energy is transformed into heat and light energy
4 0
2 years ago
Read 2 more answers
A(n) 93 kg clock initially at rest on a horizontal floor requires a(n) 610 N horizontal force to set it in motion. After the clo
denpristay [2]

Answer:0.669

Explanation:

Given

mass of clock 93 kg

Initial force required to move it 610 N

After clock sets in motion it requires a force of 514 N to keep moving it with a constant velocity

Initially static friction is acting which is more than kinetic friction

thus 613 force is required to overcome static friction

\mu _smg=610

\mu _s\times 93\times 9.8=610

\mu _s=0.669

5 0
3 years ago
A charge of 1.5 µC is placed on the plates of a parallel plate capacitor. The change in voltage across the plates is 36 V. How m
belka [17]

Answer:

Energy stored in the capacitor is U=2.7\times 10^{-5}\ J        

Explanation:

It is given that,

Charge, q=1.5\ \mu C=1.5\times 10^{-6}\ C

Potential difference, V = 36 V

We need to find the potential energy is stored in the capacitor. The stored potential energy is given by :

U=\dfrac{1}{2}q\times V

U=\dfrac{1}{2}\times 1.5\times 10^{-6}\times 36  

U = 0.000027 J

U=2.7\times 10^{-5}\ J

So, the potential energy is stored in the capacitor is U=2.7\times 10^{-5}\ J. Hence, this is the required solution.

4 0
3 years ago
Read 2 more answers
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