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3 years ago

14

Two students stand close to each other Why do they not get pulled closer to each other due to the gravitational pull they exert

on each other

1 answer:

Ainat [17]3 years ago

3 0

Answer:

there gravitational force is very less to pull the weight of a person.

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Hemoglobin (Hb) can be viewed as having two quaternary states, a low oxygen affinity state (T), and a high oxygen affinity state

natta225 [31]

<h3><u>Answer;</u></h3>

The statements that are True are;

Upon binding a molecule of oxygen, Hb undergoes a conformational change that makes the binding of subsequent O2 molecules easier.
The conformational change induced in Hb upon binding oxygen is the result of a small movement (0.2 Å) of the iron cation in the center of heme.
Site-directed mutagenesis studies have indicated that the cooperativity of O2 binding in Hb is attributable to the movement of the F helix in Hb.

<h3><u>Explanation</u>;</h3>

Hemoglobin is a key pigment in the blood that transports oxygen gas to all the tissues in the body. It is made up of two types of chains; that is two alpha chains and two beta chains.
in its deoxygenated state hemoglobin has a low affinity for oxygen compared to myoglobin. When oxygen is bound to the first subunit of hemoglobin it leads to subtle changes to the quaternary structure of the protein. This in turn makes it easier for a subsequent molecule of oxygen to bind to the next subunit.

8 0

3 years ago

What are all the elements to the left of the zigzag line in a periodic table called?

Kitty [74]

They are called metals

4 0

4 years ago

If a(n) __________ is applied, the equilibrium shifts to relieve this change in conditions.

elixir [45]

Answer:

the answer is D. stress

If a stress is applied, the equilibrium shifts to relieve this change in conditions.

6 0

2 years ago

What is the density of a mineral with a mass of 41.2 g and a volume 8.2 cm3?

dezoksy [38]

Hey there!:

mass = 41.2 g

Volume = 8.2 cm³

Therefore:

D = m / V

D = 41.2 / 8.2

D = 5.02 g/cm³

4 0

4 years ago

Read 2 more answers

A student has 100. mL of 0.400 M CuSO4(aq) and is asked to make 100. mL of 0.150 M CuSO4(aq) for a spectrophotometry experiment.

ValentinkaMS [17]

Answer:

<u></u>

<u>a. 37.5 mL</u>

<u></u>

<u>b. See the description below</u>

Explanation:

<u><em>a. Volume of 0.400 M CuSO₄(aq) required for the preparation</em></u>

In dissolutions, since the number of moles of solute is constant, the equation is:

$C_1\times V_1=C_2\times V_2$

Substitute and solve for V₁

$0.400M\times V_1=0.150M\times 100ml$

$V_1=0.150M\times 100.ml/0.400M=37.5ml$

<u><em>b. Briefly describe the essential steps to most accurately prepare the 0.150 M CuSO₄(aq) from the 0.400 M CuSO₄(aq)</em></u>

You will use the stock solution, the funnel, the buret, and distilled water.

i) Using the funnel, fill in the buret with with 50 ml of the stock solution, i.e. the 100. ml of 0.400 M CuSO₄(aq) solution.

ii) Pour 37.5 ml of the stock solution from the burete into the volumetric flask.

iii) Carefully add disitlled water to the 37.5ml of the stock solution in the volumetric flask until the mark (50 ml) on the volumetric flask.

iv) Put the stopper and rotate the volumetric flask to homegenize the solution.

3 0

4 years ago