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Anit [1.1K]
3 years ago
15

Write the expected ground electronic configuratio for the noble gas with electron occupying 4f orbitals?

Chemistry
1 answer:
lisov135 [29]3 years ago
3 0

Answer:

There are main six noble gases in the periodic table. The filling of 4f-orbitals occurs after 6s orbitals. The noble gas that belongs to the sixth period is Radon. Its electronic configuration is [ X e ] 6 s 2 4 f 14 5 d 10 6 p 6  .

Therefore, the name of noble gas is Radon.

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Whuch expression is equal to the number of grams in 2.43 kg
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2.43*1000. 

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3 years ago
A mixture of hydrochloric and sulfuric acids is prepared so that it contains 0.315 M HCl and 0.125 M H2SO4. What volume of 0.55
Xelga [282]

<u>Answer:</u> The volume of NaOH required is 402.9 mL

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .....(1)

  • <u>For HCl:</u>

Molarity of HCl solution = 0.315 M

Volume of solution = 503.4 mL = 0.5034 L   (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

0.315M=\frac{\text{Moles of HCl}}{0.5034L}\\\\\text{Moles of HCl}=(0.315mol/L\times 0.5034L)=0.1586mol

  • <u>For sulfuric acid:</u>

Molarity of sulfuric acid solution = 0.125 M

Volume of solution = 503.4 mL = 0.5034 L

Putting values in equation 1, we get:

0.125M=\frac{\text{Moles of }H_2SO_4}{0.5034L}\\\\\text{Moles of }H_2SO_4=(0.125mol/L\times 0.5034L)=0.0630mol

As, all of the acid is neutralized, so moles of NaOH = [0.1586 + 0.0630] moles = 0.2216 moles

Molarity of NaOH solution = 0.55 M

Moles of NaOH = 0.2216 moles

Putting values in equation 1, we get:

0.55M=\frac{0.2216}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.2216}{0.55}=0.4029L=402.9mL

Hence, the volume of NaOH required is 402.9 mL

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The coefficients in a balanced chemical equation are important because they give the ratio of the reactants and the products. Those ratios are fixed and when the reagents react do it in the same proportion and yield the products in the same proportion of the coefficients. Then, the coefficients are the basis for the calculations of the amount of substances that react and the amount of substances that are formed as result of the reaction.
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