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2 years ago

15

The figure shows an arrangement in which four disks are suspended by cords. The longer, top cord loops over a frictionless pulle

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and pulls with a force of magnitude 91.7 N on the wall to which it is attached. The tensions in the shorter cords are T1 = 59.2 N, T2 =
33.4 N, and T3 = 9.65 N. What are the masses of (a) disk A. (b) disk B, (c) disk C, and (d) disk D?
11
79

1 answer:

garik1379 [7]2 years ago

7 0

Answer:

A) m = F/a = 91.7/9.81 = 9.35 kg

B) m = F/a = 59.2/9.81 = 6.03 kg

C) m = F/a = 33.4/9.81 = 3.40 kg

D) m = F/a = 9.65/9.81 = 0.984 kg

Explanation:

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Approximately 1.62 × 10⁻⁴ V.

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The average EMF in the coil is equal to

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By Faraday's Law of Induction, the EMF $\epsilon$ induced in a coil (one loop) is equal to the rate of change in the magnetic flux $\Phi$ through the coil.

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However, by the Fundamental Theorem of Calculus, integration reverts the action of differentiation. That is:

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$\Phi = B \cdot A \cdot N \; \sin{\theta}$ .

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$\theta$ is the angle between the field lines and the coil.
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Final flux: $\Phi(0.7) = \rm 1.1136\times 10^{-4}\; Wb$ .

Average EMF, which is the same as the average rate of change in flux:

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