Question

The figure shows an arrangement in which four disks are suspended by cords. The longer, top cord loops over a frictionless pulley
and pulls with a force of magnitude 91.7 N on the wall to which it is attached. The tensions in the shorter cords are T1 = 59.2 N, T2 =
33.4 N, and T3 = 9.65 N. What are the masses of (a) disk A. (b) disk B, (c) disk C, and (d) disk D?
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Answer 1

Answer:

A) m = F/a = 91.7/9.81 = 9.35 kg

B) m = F/a = 59.2/9.81 = 6.03 kg

C) m = F/a = 33.4/9.81 = 3.40 kg

D) m = F/a = 9.65/9.81 = 0.984 kg

Explanation: