CS2 + 3O2 = CO2 + 2SO2
1 mole of CS2 gives 1 mole of CO2
12 + 2(32) = 76g of CS2 yields 44 g of CO2
Theoretically 1 g of CS2 yields 44/76 g CO2
Therefore 50 g CS2 should yield 50*44 / 76 = 28.95 g
So % yield = 103.6 % ( which is not possible because you can't create matter from nothing).
The 30g cannot be right . This is experimental err.
. How many joules of heat are absorbed to raise
the temperature of 37 grams of water from 25°C
to 75°C?
Ans: 15.1 grams
Given reaction:
Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3
Mass of Na2CO3 = 20.0 g
Molar mass of Na2CO3 = 105.985 g/mol
# moles of Na2CO3 = 20/105.985 = 0.1887 moles
Based on the reaction stoichiometry: 1 mole of Na2CO3 produces 2 moles of NaOH
# moles of NaOH produced = 0.1887*2 = 0.3774 moles
Molar mass of NaOH = 22.989 + 15.999 + 1.008 = 39.996 g/mol
Mass of NaOH produced = 0.3774*39.996 = 15.09 grams
739 is the number of atoms of O in 92.3 moles of Cr3(PO4)2.
Explanation:
Molecular formula given is = Cr3(PO4)2
number of moles of the compound is 92.3 moles
number of 0 atoms in 92.3 moles =?
From the chemical formula 1 mole of the compound has 8 atoms of oxygen
So, it can be written as
1 mole Cr3(PO4)2 has 8 atoms of oxygen
92.3 moles of Cr3(PO4)2 has x atoms of oxygen
= 
x = 8 x 92.3
x = 738.4 atoms
There will be 739 oxygen atoms in the 92.3 moles of Cr3(PO4)2.