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yarga [219]
3 years ago
8

Which descriptions best fit the labels? X: kinetic energy Y: potential energy X: potential energy Y: kinetic energy X: mechanica

l energy Y: electrical energy X: electrical energy Y: mechanical energy
Physics
1 answer:
Pani-rosa [81]3 years ago
3 0
W-APE. For example, work W done to accelerate a positive charge from rest is positive and results from a loss in PE, or a negative APE. There must be a minus sign in front of APE to make W positive. PE can be found at any point by taking one point as a reference and calculating the work needed to move a charge to the other point.

( The capital A’s in the words are supposed to be triangles ! I also hoped this helped ! Please mark me as brainliest !! )
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420 hg = _____ cg help please
kondaur [170]
4200000 is your answer hope this helps
4 0
3 years ago
Read 2 more answers
Suppose an object’s initial velocity is 10 m/s and its final velocity is 4 m/s. Mass is constant.
Ostrovityanka [42]

The correct answer is:

Work is negative, the environment did work on the object, and the energy of the system decreases.

In fact, the work-energy theorem states that the work done by the system is equal to its variation of kinetic energy:

W=\Delta K=K_f -K_i

In this problem, the variation of kinetic energy \Delta K is negative (because the final velocity is less than the initial velocity), so the work is negative, and this means that the environment did work on the object, and its energy decreased.

3 0
2 years ago
Read 2 more answers
A 12.8-kg monkey hangs from a cord suspended from the ceiling of an elevator. The cord can withstand a tension of 156N and break
Varvara68 [4.7K]

Answer:

2.4 m/s^2

Downward

Explanation:

We are given that

Mass of monkey=12.8 kg

Tension=156 N

We have to find the magnitude of the elevator's minimum acceleration.

T=m(g+a)

Where g=9.8 m/s^2

Substitute the values

156=12.8(a+9.8)

9.8+a=\frac{156}{12.8}=12.2

a=12.2-9.8=2.4 m/s^2

Hence, the acceleration =a=2.4 m/s^2

Direction of the elevator's minimum acceleration is downward because the elevator moves downwards.

8 0
3 years ago
What is the magnitude and direction (right or left) of the
Sunny_sXe [5.5K]

Answer: 12 N to the right

Explanation:

If we calculate the net force acting on the box, we will have:

<u>In y-component:</u>

Fy_{net}=F_{n}+F_{g} (1)

Where F_{n}=12 N is the Normal force, directed upwards and F_{g}=-12 N is the weight of the box (gravity force), directed downwards.

Fy_{net}=12 N-12 N (2)

Fy_{net}=0 N (3) Hence the net force in the vertical component is zero

<u>In x-component:</u>

Fx_{net}=F_{left}+F_{right} (4)

Where F_{left}=-3 N and F_{right}= 15 N

Fx_{net}=-3 N + 15 N (5)

Fx_{net}=12 N (6) This is the net force in the horizontal component

Therefore, the total net force acting on the box is 12 N directed to the right

5 0
2 years ago
A van is traveling with an initial velocity of 12 m/s. The driver takes a time of 45 seconds to speed up to a velocity of 20 m/s
Rufina [12.5K]
  • Initial velocity=u=12m/s
  • Final velocity=v=20m/s
  • Time=t=45s

\\ \rm\hookrightarrow Acceleration=\dfrac{v-u}{t}

\\ \rm\hookrightarrow Acceleration=\dfrac{20-12}{45}

\\ \rm\hookrightarrow Acceleration=\dfrac{8}{45}

\\ \rm\hookrightarrow Acceleration=0.1m/s^2

Now

  • Distance=s

\\ \rm\hookrightarrow v^2-u^2=2as

\\ \rm\hookrightarrow (20)^2-12^2=2(0.1)s

\\ \rm\hookrightarrow 400-144=0.2s

\\ \rm\hookrightarrow 256=0.2s

\\ \rm\hookrightarrow s=\dfrac{256}{0.2}

\\ \rm\hookrightarrow s=1280m

4 0
2 years ago
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