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DochEvi [55]
3 years ago
12

Please help answer this Guy's​ HELP it's very Important

Chemistry
1 answer:
quester [9]3 years ago
8 0

I cant really help you tight now sorry

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Name the acid and base needed to form the salt ammonium nitrate give the chemical reaction
velikii [3]

Answer:

here

Explanation:

(NH4NO3), a salt of ammonia and nitric acid, ....4 and 3 are sub script

A neutralization reaction is a chemical reaction where an acid and a base are combined with the intent of producing a neutral pH level.

4 0
2 years ago
Read 2 more answers
You have 7.86 x 10^23 molecules of NaCl. This would be equal to ___ grams of NaCl.
sergij07 [2.7K]

7.86 \times 10 {}^{23} atoms \\  \frac{7.86}{6.022}  \times  \frac{10 {}^{23} }{ {10}^{23} }   = 1.305\: moles

1.305 × (23+35.5) = 76.34 grams

3 0
3 years ago
If “A” is a halogen in the formal equation, A + BC -> __, what letter would it be replacing?
mylen [45]
Answer is: it would replace letter C.
Halogen elements are fluorine, chlorine, bromine and iodine, they are nonmetals. In compound BC, letter C represents nonmetal, so nonmetal replaces nonmetal in single replacement reaction.
Single replacement reaction <span>is a reaction in which one element is substituted for another element in a compound.</span>
7 0
3 years ago
The chemical equation below shows the reaction of methane (CH4) and oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O)
Yuki888 [10]
Carbon dioxide and water are the products
8 0
3 years ago
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Calculate the friction of the person on ski. We use the situation from example 5.1 "Skiing Exercise" from the text book, but we
nalin [4]

Answer: Friction (Fk) = 46.2N.

Explanation: In the attachment, there is the drawing of the forces acting on the skiing person. As the person is in movement, the formula to calculate the friction is Fk = μk.N, where μk is the coefficient of kinetic friction and N is normal force. Normal force is the force necessary to keep a person "above" the ground. To find the normal force as suggested, we use the representation of the forces in the attachment. With it, it's shown that to calculate N:

cos 15° = \frac{N}{Fg}

N = Fg·cos 15°

N = 608·(-0.76)

N = - 461.9N

Now, with N and knowing the coefficient, which can be found in Physics Text Books and it is 0.1, we have:

Fk = 0.1·(-461.9)

Fk = - 46.2N

The friction is negative because it is pointing to the opposite side of the reference.

5 0
3 years ago
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