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Ksju [112]
3 years ago
10

To launch a rocket, liquid oxygen and liquid hydrogen are combined inside the rocket engine to react explosively. How do you thi

nk scientists take into account the law of conservation of mass when they calculate the amount of fuel needed for a rocket launch?
Chemistry
1 answer:
KIM [24]3 years ago
3 0

Answer:

Explanation:

In this chemistry lab, students investigate how to build and launch a simple rocket that uses hydrogen and oxygen gases that will be mixed to propel the rocket (large bulb plastic pipette). Students will understand the principles of combustion reactions, kinetics, stoichiometry of reactions, activation energy, explosive mixtures, rocketry, and different types of chemical reactions. Students will explore and determine the proportions of hydrogen and oxygen mixture that will achieve the best launch results. Students will compare the balanced chemical reaction of hydrogen and oxygen with their lab results; students should discover that the optimal distance occurs when the mixture of hydrogen and oxygen is two to one hydrogen, oxygen mixture ratio and this can be determined theoretically from the balanced chemical reaction equation. Students will perform the lab, collect data, and discuss, compare, and contrast their lab findings with the balanced chemical reaction equation. Students will present their structured inquiry investigations using a power-point presentation. Other groups along with the teacher will assess each group by using a provided rubric. Group assessments will be the deciding assessment for the final lab score. A follow up activity could investigate how NASA scientists launch real rockets into space and propose a procedure to investigate and collect data on a launching a heavier object at the school football field.

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What is the ph of a 0.45 m solution of aniline (c6h5nh2)? (pkb  9.40)?
mote1985 [20]

Answer is: pH of aniline is 9.13.<span>
Chemical reaction: C</span>₆H₅NH₂(aq)+ H₂O(l) ⇌ C₆H₅NH₃⁺(aq) + OH⁻(aq).

pKb(C₆H₅NH₂) = 9.40.

Kb(C₆H₅NH₂) = 10∧(-9.4) = 4·10⁻¹⁰.

c₀(C₆H₅NH₂) = 0.45 M.

c(C₆H₅NH₃⁺) = c(OH⁻) = x.

c(C₆H₅NH₂) = 0.45 M - x.

Kb = c(C₆H₅NH₃⁺) · c(OH⁻) / c(C₆H₅NH₂).

4·10⁻¹⁰ = x² /  (0.45 M - x). 

Solve quadratic equation: x = c(OH⁻) = 0.0000134 M.

pOH = -log(0.0000134 M.) = 4.87.

pH = 14 - 4.87 = 9.13.

7 0
3 years ago
[OH-] for a solution is
solong [7]

Answer:

B = basic

Explanation:

Given data:

[OH⁻] = 5.35×10⁻⁴M

pH = ?

Solution:

pOH = -log[OH⁻]

pOH = - [5.35×10⁻⁴]

pOH = 3.272

it is known that,

pH + pOH = 14

pH = 14- pOH

pH = 14 - 3.272

pH = 10.728

The acidic pH is range from zero to less than 7 while 7 pH is neutral and above 7 the pH is basic. So, the given solution is basic.

8 0
3 years ago
Read 2 more answers
Instrument used to measure atmospheric pressure
lisov135 [29]

Answer: barometer

Explanation:

7 0
3 years ago
How can the rate constant be determined from the rate law?
Vinil7 [7]

Answer:

B. The rate constant is the reaction rate divided by the concentration

terms.

Explanation:

The rate constant can be determined from the rate law because it is the reaction rate divided by the concentration terms. I hope I could help! :)

7 0
2 years ago
How are the molecular mass and molar mass of a compound similar and how are they different?
4vir4ik [10]

Answer:

Similarities: both state the mass of chemical species and they have the same numerical value

Differences: molecular mass refers to one single molecule and molar mass refers to one mole of a molecule

Explanation:

The molecular mass is the value of the mass of each molecule and it is measured in mass units (u). It is calculated adding the mass of each atom of the molecule.

The molar mass is the value of the mass of one mole of molecules, which means the mass of 6.022140857 × 10²³ molecules. The unit is g/mol.

For example, we can consider the methane molecule, which has the chemical formula of CH₄:

Molecular mass CH₄ = C mass + 4 x (H mass)

Molecular mass CH₄ = 12.01 + 4 x (1.01)

Molecular mass CH₄ = 16.05 u

Now to calculate the molar mass we multiply the value of the molecular mass by the Avogadro number and convert the units to g/mol:

Molar mass CH₄: 16.05 x \frac{1}{6.022140857 x 10x^{23} } g x 6.022140857 × 10²³ mol⁻¹

Molecular mass CH₄ = 16.05 g / mol

5 0
3 years ago
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