Answer:
∆t(f) = 49.755C
Explanation:
Freezing point is defined as the point in which a liquid changes from liquid to solid state. Therefore, to calculate the freezing point of aqueous solution of propanol
∆t = k × I × m
Where k is cryscopic constant =
I = vant Hoff factor = 2
M = molar concentration = 12.25m
∆t (f) = 1.9 × 12.25 × 2 = 49.755C
If a<span> student used 10 mL water instead of 30 mL for extraction of salt water from mixture, the extraction of salt will be lesser than compared to using 30 mL since less solute will dissolve in 10 mL.</span>
Answer:
your question is incomplete and its
![6.02 \times {10}^{23?}](https://tex.z-dn.net/?f=6.02%20%5Ctimes%20%20%7B10%7D%5E%7B23%3F%7D%20)
particles which is one mole of a substance
Explanation:
you can solve the question by using this formular 1 mole of a substance=mass of the substance/ its molar mass
you find molar mass of a compound by adding individual molar masses of elements in that compound
Volume:
2.00 x 11.0 x 11.0 => 242 cm³
mass : 213 g
D = m / V
D = 213 / 242
D = 0.880 g/cm³
Answer B
hope this helps!