To launch a rocket, liquid oxygen and liquid hydrogen are combined inside the rocket engine to react explosively. How do you thi
1 answer:
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Explanation:
It is known that charge on xenon nucleus is equal to +54e. And, charge on the proton is
equal to +e. So, radius of the nucleus is as follows.
r =
= 3.0 fm
Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.
d = r + 2.5
= (3.0 + 2.5) fm
= 5.5 fm
= (as 1 fm =
)
Therefore, electrostatic repulsive force on proton is calculated as follows.
F =
Putting the given values into the above formula as follows.
F =
=
=
= 411.2 N
or, = N
Thus, we ca conclude that N is the electric force on a proton 2.5 fm from the surface of the nucleus.
Answer:
-1, -4
Explanation:
Factoring, you get:
To find what x can be, you need to realize what could make this equation true. To set the left side equal to 0, either one of the terms in parentheses must be equal to 0. To do that, x must be the negative of the other term, so that they can cancel each other out. Therefore, x is -4 and -1. Hope this helps!