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max2010maxim [7]
3 years ago
14

The general form for a double replacement reaction is

Chemistry
1 answer:
yawa3891 [41]3 years ago
7 0

Answer:

A is the right answer

Explanation:

In double replacement reaction two compounds combines to give other two compounds

As example:

CaCl2 + 2AgNO3 = Ca(NO3)2+ 2AgCl

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The SI base unit for mass is the gram. TRUE FALSE ​
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1. What is the molarity of a solution prepared by dissolving 3.11 grams of NaOH in
Elena L [17]

The molarity of a solution prepared by dissolving 3.11 grams of NaOH in

enough water to make 300 milliliters of solution is 0. 256 mol/ L

Explanation:

<h3>What is Molarity?</h3>

Molarity (M) is the amount of a substance in a given volume of solution. It is otherwise known as the number of moles of solute in a certain amount of solution.

The unit of molarity is mol/L

<h3>Formula for calculating molarity :</h3>

Molarity = number of moles of solute divided by the volume of the solution\

<h3>Parameters </h3>

Molarity = ?

Number of  moles is calculated using :

Mass of the solute = 3.11 grams of NaOH

Molar mass of the solute = Na + O + H

Let's input the atomic numbers of the elements: Na (23) , O (16) , H (1)

Molar mass of NaOH = 23 + 16 + 1 = 40 g/ mol

Number of moles = 3.11 ÷ 40 = 0.077 mol

Volume of the solution is measured in Liters

Let's convert 300 milliters to liters = 300 divided by 1000 = 0.3 Liters

Molarity = 0.077 ÷ 0.3 = 0. 256 mol/ L

Therefore, the Molarity of the solution is 0. 256 mol/ L

Read more on molarity here :

brainly.com/question/26873446

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1 year ago
When the reaction shown is correctly balanced, the coefficients are HNO3 + KOH → KNO3 + H2O
GuDViN [60]
Coefficients are 1,1,1,1
4 0
3 years ago
The pH of a basic solution is 9.77. What is [OH⁻]?
uysha [10]

The  [OH⁻] of the solution is 5.37×10⁵ M.

<h3 /><h3>What is pOH?</h3>

This is the negative logarithm to base 10 of hydroxy ion [OH⁻] concentration.

To calculate the hydroxy ion [OH⁻] concentration we use the formula below.

Note:

  • pH+pOH = 14
  • pOH = 14-pH
  • pOH = 14-9.77
  • pOH = 4.27

Formula:

  • [OH⁻] = 1/10^{pOH}................. Equation 1

Given:

  • pOH = 4.27

Substitute the value into equation 1

  • [OH⁻] = 1/10^{4.27}
  • [OH⁻]  = 5.37×10⁵

Hence, The [OH⁻] of the solution is 5.37×10⁵ M.

Learn more about hydroxy ion concentration here: brainly.com/question/17090407

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