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2 years ago

The general form for a double replacement reaction is

Chemistry

1 answer:

yawa3891 [41]2 years ago

7 0

Answer:

A is the right answer

Explanation:

In double replacement reaction two compounds combines to give other two compounds

As example:

CaCl2 + 2AgNO3 = Ca(NO3)2+ 2AgCl

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To which group of the periodic table do lithium and potassium belong?

s344n2d4d5 [400]

Answer:

1)alkali metals

2)1g/ml

3) mercury

Explanation:

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have a good day

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carryonlearing

6 0

1 year ago

Read 2 more answers

9) Which element in each pair has the larger ionization energy?

erastovalidia [21]

I think the answer is C.

6 0

2 years ago

Sodium phosphate is added to a solution that contains 0.0030 M aluminum nitrate and 0.016 M calcium chloride. The concentration

gavmur [86]

Explanation:

It is given that aluminium nitrate and calcium chloride are mixed together with sodium phosphate.

And, $K_{sp} of AlPO_{4} = 9.84 \times 10^{-21}$

$K_{sp} of Ca_{3}(PO_{4})_{2} = 2.0 \times 10^{-29}$

Let us assume that the solubility be "s". And, the reaction equation is as follows.

$AlPO_{4} \rightleftharpoons Al^{3+} + PO^{3-}_{4}$

$9.84 \times 10^{-21} = s \times s$

s = $9.92 \times 10^{-11}$

Also, $Ca_{3}(PO_{4})_{2} \rightleftharpoons 3Ca^{2+} + 2PO^{3-}_{4}$

$2 \times 10^{-29} = (3s)^{3} \times (2s)^{2}$

s = $7.14 \times 10^{-7}$

This means that first, aluminium phosphate will precipitate.

Now, we will calculate the concentration of phosphate when calcium phosphate starts to precipitate out using the $K_{sp}$ expression as follows.

$K_{sp} = [Ca^{2+}]^{3}[PO^{3-}_{4}]^{2}$

$2.0 \times 10^{-29} = (0.016)^{3}[PO^{3-}_{4}]^{2}$

$2.0 \times 10^{-29} = 4.096 \times 10^{-6} \times [PO^{3-}_{4}]^{2}$

$[PO^{3-}_{4}]^{2}$ = $4.88 \times 10^{-24}$

= $2.21 \times 10^{-12}$ M

Similarly, calculate the concentration of aluminium at this concentration of phosphate as follows.

$AlPO_{4} \rightleftharpoons Al^{3+} + PO^{3-}_{4}$

$K_{sp} = [Al^{3+}][PO^{3-}_{4}]$

$9.84 \times 10^{-21} = [Al^{3+}] \times 2.21 \times 10^{-12}$

$[Al^{3+}] = 4.45 \times 10^{-9}$ M

Thus, we can conclude that concentration of aluminium will be $4.45 \times 10^{-9}$ M when calcium begins to precipitate.

7 0

2 years ago

How many photons are produced in a laser pulse of 0.897 J at 407 nm?

Leona [35]

The relationship between energy of a single photon and its wavelength can be determined using the formula E=hc/lambda where E is energy, h is Planck's constant, c is the speed of light, and lambda is photons.

Before being able to solve for energy, need to convert nanometers to meters.

407 nm (1 m/1 x 10^9 nm) = 4.07 x 10^-7 m

Then plug in the values we know into the equation.
E h(Planck's constant) c(speed of light)
E = (6.63 x 10^-34 Js)(3 x 10^8 m/s) / 4.07 x 10^-7 m (lambda)

E=(0.000000000000000000000000000000000663js)(300,000,000m/s)=1.989×10^-25j/ms

E=1.989x10^-25j/ms /{divided by} 4.07x10^-7m = 4.8869779x10^-33 J (the meters cancel out)

E = 4.89 x 10^-33 J

This gives us the energy in Joules of a single photon. Now, we can find the number of photons in 0.897 J

0.897J / 4.89 x 10^-33 J = ((0.897 J) / 4.89) x ((10^(-33)) J) = 1.8343558 x 10^-34

1.83435583 × 10-34m4 kg2 / s4 photons

4 0

3 years ago

Describe what acceleration is in words and give the formula (a = ???)

alexandr402 [8]

Answer:

Acceleration = (v Final −v Initial)/(t Final −t Initial). Where v stands for velocity and t stands for time. In algebraic notation, the formula can be expressed as: a=Δv/Δt; Acceleration can be defined as the rate of change of velocity with respect to time.

7 0

2 years ago