A rat runs 2m right, turns around and runs 3m left. Then goes 2m right. What is its displacement?

Physics

1 answer:

geniusboy [140]3 years ago

7 0

Answer:

Explanation:

I think this answer would be 1m to the left.

You might be interested in

Which statement is true about an object moving in a circular motion due to centripetal force, F, when the mass is doubled?

marshall27 [118]

Ans) A) Centripetal force will be doubled.

See centripetal force F = mv^2/r

That means centripetal force is directly proportional to the mass of the particle

So, if we double the mass, centripetal force will be increased by twofolds.

So, option A) is correct.

Now, looking at the other options,

B) says centripetal force is unaltered which is incorrect as centripetal force has been altered and increased twofold.

Option C) and D) reduces centripetal force which are also not possible here.

So, only Option A) is correct

4 0

4 years ago

Who will give me answer I will give you brainliest.....

kondaur [170]

1 . W=mass times acceleration due to gravity
60kg times 9.8m/s2
= 588N

2. W=mg
1176N=m times 9.8
m=120kg

3. 1 hour=3600s
24 hours=?
24 times 3600
= 86400 seconds

4. 1000g=1kg
25000g=?
25000 times 1 divide by 1000
=25kg

5. 1000000mg=1kg
123000000=?
123000000 times 1 divide by 1000000
=123 kg

7 0

3 years ago

You want to manufacture a guitar such that the instrument will be in tune when each of the strings are tightened to the same ten

charle [14.2K]

Answer:

0.000507 kg/m

Explanation:

L = Length of string

T = Tension

$\mu$ = Mass density of string

E denotes the E string

D denotes the D String

Frequency is given by

$f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}$

$f\propto \sqrt{\dfrac{1}{\mu}}$

$\dfrac{f_D}{f_E}=\sqrt{\dfrac{\mu_E}{\mu_D}}\\\Rightarrow \mu_E=\dfrac{f_D^2}{f_E^2}\mu_D\\\Rightarrow \mu_E=\dfrac{146.83^2}{329.63^2}\times 0.00256\\\Rightarrow \mu_E=0.000507\ kg/m$