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3 years ago

12

Solve the equation 2/3x-6=9

2 answers:

Anestetic [448]3 years ago

6 0

Answer: 2/3-6=9 is equal to = − 2(2x+6)

Umnica [9.8K]3 years ago

3 0

Answer:

x = 45 over 2 or 22.5

Step-by-step explanation:

ADD 6 to both sides of the equation
Simplify
Multiply 3 by the same value to eliminate fraction denominators
Simplify
Divide 2 by both sides of the equation by the same term
Simplify

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There are 8 students on the minibus.five of students are boy. What fraction of the students are boys?

kolezko [41]

5/8 i think im pretty sure tho

5 0

4 years ago

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How can you solve this problem <br> 2250=5000 x R x 5

vesna_86 [32]

R is equal to 450

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-2250=Rx5
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5 0

3 years ago

What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE

maks197457 [2]

Given:

The equation of a line is:

$2y+3x=10$

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

$2y+3x=10$

For $x=0$ ,

$2y+3(0)=10$

$2y+0=10$

$y=\dfrac{10}{2}$

$y=5$

For $x=2$ ,

$2y+3(2)=10$

$2y+6=10$

$2y=10-6$

$2y=4$

Divide both sides by 2.

$y=\dfrac{4}{2}$

$y=2$

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

$(x,y)\to (3x,3y)$

Using this rule, we get

$A(0,5)\to A'(3(0),3(5))$

$A(0,5)\to A'(0,15)$

Similarly,

$B(2,2)\to B'(3(2),3(2))$

$B(2,2)\to B'(6,6)$

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-15=\dfrac{6-15}{6-0}(x-0)$

$y-15=\dfrac{-9}{6}(x)$

$y-15=\dfrac{-3}{2}x$

Multiply both sides by 2.

$2(y-15)=-3x$

$2y-30=-3x$

$2y+3x=30$

Therefore, the equation of the line after the dilation is $2y+3x=30$ .

3 0

3 years ago

I need some help, please. 25 points. : )

Svetlanka [38]

the awnser is -6

im very sure let me know if im wrong.

4 0

2 years ago

I will give brainliest to whoever helps me with this question. Also, if you could please explain to me how you solved it I would

kolbaska11 [484]

I will try to help okay i will send my friends to help

6 0

3 years ago

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