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faltersainse [42]
3 years ago
11

What is the solution to lemonade

Chemistry
2 answers:
harkovskaia [24]3 years ago
7 0
If you mean what is in the solution, then that would be water, sugar, and lemonade powder (That is, if it is not homemade). If this is homemade lemonade, then is is water, sugar, lemon juice, and if you've ever seen homemade lemonade, there's also little bits of lemon floating around too, in which case this would technically be a suspension rather than a solution.
elixir [45]3 years ago
3 0
Lemons first then sugar then water then water and mix i do it like that first but people do it another way 

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By calculating it's number of GROUP........
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What is the formula for the ionic compound formed between calcium and sulfur?
zheka24 [161]

Answer:

CaS

Explanation:

calcium is Ca2+ and sulfur is S2- because the charges are equal you only need one of  each atom, so the answer is CaS

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Which medical condition(s) can prevent molecules from entering the cell?
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A generic weak acid with formula HA has a Ka = 2.76 x 10-8. Calculate the Kb for the conjugate base of the acid.
Reika [66]

Answer:

3.62x10⁻⁷ = Kb

Explanation:

The acid equilibrium of a weak acid, HX, is:

HX + H₂O ⇄ X⁻ + H₃O⁺

Where Ka = [X⁻] [H₃O⁺] / [HX]

And basic equilibrium of the conjugate base, is:

X⁻ + H₂O ⇄ OH⁻ + HX

Where Kb = [OH⁻] [HX] / [X⁻]

To convert Ka to Kb we must use water equilibrium:

2H₂O ⇄ H₃O⁺ + OH⁻

Where Kw = 1x10⁻¹⁴ = [OH⁻] [H₃O⁺]

Thus, we can obtain:

Kw = Ka*Kb

Solving for Kb:

Kw / Ka = Kb

1x10⁻¹⁴ /  2.76x10⁻⁸ =

3.62x10⁻⁷ = Kb

4 0
3 years ago
A 2.17 gm sample barium reacted completely with water what is the equation for the reaction how many milliliters of dry H2 evole
vaieri [72.5K]

Answer:

400 mL

Explanation:

Given data:

Mass of barium = 2.17 g

Pressure = 748 mmHg (748/760 = 0.98 atm)

Temperature = 21 °C ( 273+ 21 = 294k)

Milliliters of H₂ evolved = ?

Solution:

chemical equation:

Ba + 2H₂O →  Ba(OH)₂ + H₂

Number of moles of barium:

Number of moles = mass/ molar mass

Number of moles = 2.17 g / 137.327 g/mol

Number of moles = 0.016 mol

Now we  will compare the moles of barium with H₂.

                       Ba        :       H₂

                         1         :         1

                  0.016        :     0.016

Milliliters of H₂:

PV = nRT

V = nRT/P

V = 0.016 mol ×  0.0821 atm. mol⁻¹.k⁻¹.L×294 k/0.98 atm

V = 0.39 atm. L/0.98 atm

V = 0.4 L

L to mL

0.4 × 1000 = 400 mL

8 0
3 years ago
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