Answer:
v = 10 V and E = 2 10³ N/C
Explanation:
The electrical potentials and the electric field at one point are related by the expression
ΔV = - ∫ E. dS
Where the bold indicates vector quantities, E is the electric field and S is the line of displacement of the load, in general displacement is perpendicular to the equipotential lines, which reduces the product scales to the ordinary product.
If the potential difference is the most usual that is V = 10 V, the electric field is
s = 0.5 cm = 0.5 10⁻² m
E = ΔV / S
E = 10/0.5 10⁻²
E = 2 10³ N / C
I think that the question is simply asking whether the statement is correct.
The statement is wrong! The scientific endeavor (the work of the scientists, the pursue of knowledge) can be potentially harmful. For example, many tests of human medicine have to be performed on animals, and often the medicine causes great suffering in the animals (and gets rejected for testing on humans).
The lightbulb that carries more current will be the 25W bulb.
<h3>How to explain the information?</h3>
It should be noted that an electric current simply means the stream of charged particles that move through an electrical conductor or space.
In this case, it should be noted that the power is the same for both bulbs. Therefore, the 25W bulb will have the higher resistance so that it will have lower power.
Therefore, the lightbulb that carries more current will be the 25W bulb.
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Answer:
0.46km
Explanation:
45963cm/100cm=459.63m/1000m=0.45963 or 0.46km
Increasing a car's speed from 0 mph to 30 mph requires more work than that of 50 mph to 60 mph.
<h3>What is work?</h3>
Work is a measure of energy expended in moving an object. It is calculated by multiplying the force by the distance.
According to this question, work is required to move a car from one position to another.
The distance moved from 0 - 30mph is more than that moved from 50 - 60mph, therefore, increasing a car's speed from 0 mph to 30 mph requires more work than that of 50 mph to 60 mph.
Learn more about work at: brainly.com/question/19382352
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