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3 years ago

If Mars were 10 times closer to the Sun, then the Sun would attract Mars with

2 answers:

7 0

The velocity does not change greatly between Mars and Venus —explained Dong— but Venus's closer proximity to the sun boosts the density by almost a factor of 4.5. This would mean that atmosphere on Mars would be lost even more rapidly than at its current position.

Goshia [24]3 years ago

4 0

Answer:

Explanation:

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What do they need to do to determine what time period Eocene belongs to on the geologic time scale

Norma-Jean [14]

They need to scan a chart on the internet and you know when you find it.

7 0

3 years ago

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If a woman runs 100 meters north and then 70 meters south, what is her total displacement?

Burka [1]

Displacement is the distance between the starting and ending points, in the direction from the starting point to the ending point, all regardless of the route followed from the starting point to the end point.

The woman's displacement is therefore 30 meters north.

8 0

3 years ago

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The index of refraction for red light in water is 1.331 and that for blue light is 1.340. If a ray of white light enters the wat

kobusy [5.1K]

Answer:

Angle of refraction for red light is $43.01^{\circ}$

Angle of refraction for blue light is $42.68^{\circ}$

Explanation:

It is given refractive index for red light is $\mu _{red}=1.331$

Refractive index of blue light $\mu _{blue}=1.340$

Angle of incidence $i=65.30^{\circ}$

According to law of refraction $\mu =\frac{sini}{sinr}$

For red light $1.331 =\frac{sin65.30^{\circ}}{sinr}$

$1.331 =\frac{0.908}{sinr}$

$sinr=0.682$

$r=43.01^{\circ}$

Therefore angle of refraction for red light is $43.01^{\circ}$

Similarly for blue light $1.340 =\frac{sin65.30^{\circ}}{sinr}$

$1.340 =\frac{0.908}{sinr}$

$sinr=0.677$

r = $42.68^{\circ}$

Therefore angle of refraction for blue light is $42.68^{\circ}$

6 0

3 years ago

A heavy frog and a light frog jump straight up into the air. They push off in such away that they both have the same kinetic ene

Ilia_Sergeevich [38]

Answer:

The lighter frog goes higher than the heavier frog.

The lighter frog is moving faster than the heavier frog

Explanation:

If both frogs have the same kinetic energy when they leave the ground, the following equality applies:

$K(light) = K(heavy) = \frac{1}{2} *ml*vol^{2} = \frac{1}{2}*mh*voh^{2}$

Now, if the only force acting on the frogs is gravity, when they reach to the maximum height, we can apply the following kinematic equation:

$vf^{2} -vo^{2} = 2*a*hmax = vf^{2} -vo^{2} = 2*(-g)*hmax$

When h= hmax, the object comes momentarily to an stop, so vf =0

Solving for hmax:

$hmax =\frac{vo^{2} }{2*g}$

As the lighter frog, in order to have the same kinetic energy than the heavier one, has a greater initial velocity, it will go higher than the other.

As a consequence of both having the same kinetic energy, the lighter frog will be moving faster than the heavier frog.

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3 years ago

In a new lab experiment, two parallel vertical metal rods are separated by L = 1.4 m . A R = 2.0-Ω resistor is connected from th

artcher [175]

Answer:

Explanation:

Let v be the terminal velocity of the bar .

emf induced in the bar of length L

= B L v where B is the value of magnetic field.

current i in the circuit containing resistance R

i = induced emf / R

BLv / R

Magnetic force in upward direction in the bar

F = BiL

= BL x BLv / R

B²L²v / R

For attainment of uniform velocity

magnetic force = weight

B²L²v / R = mg

so current

i = BLv / R

8 0

3 years ago

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