Answer:
<h3>The binding energy of sodium Na=<em>5.407791×10⁹J</em></h3>
Explanation:
<h3>Greetings !</h3>
Binding energy, amount of energy required to separate a particle from a system of particles or to disperse all the particles of the system. Binding energy is especially applicable to subatomic particles in atomic nuclei, to electrons bound to nuclei in atoms, and to atoms and ions bound together in crystals.
<h2>Formula : Eb=(Δm)c²</h2><h3>where:Eb= binding energy</h3><h3> .Δm= mass defect(kg)</h3><h3> c= speed of light 3.00×10⁸ms¯¹</h3><h2 /><h3>
<u>Given</u><u> </u><u>values</u></h3>
- m= 18.02597
- c=3.00×10⁸ms¯¹
<h3><u>required </u><u>value</u></h3>
<h3><u>Solution:</u></h3>
- Eb=(Δm)c²
- Eb=(18.02597)*(3.00*10⁸ms¯¹
- Eb=5.407791*10⁹J
Answer:
The total charge Q of the sphere is 
.
Explanation:
Given that,
Radius = 5 cm
Charge density 
We need to calculate the total charge Q of the sphere
Using formula of charge
Where, 
= charge density
V = volume
Put the value into the formula
Put the value into the formula
Hence, The total charge Q of the sphere is .
Answer:
v = 12.12 m/s
Explanation:
It is given that,
Radius of circle, r = 30 m
The coefficient friction between tires and road is 0.5,
The centripetal force is balanced by the force of friction such that,
v = 12.12 m/s
So, the maximum speed with which this car can round this curve is 12.12 m/s. Hence, this is the required solution.
It’s an assortment of compound molecules
