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The two forces acting on the object would be 1. Weight because of gravity pulling the object toward the ground and 2. Drag resisting this motion
Answer
given,
k = 250 N/m
q = 900 N/m³
(FSp)s=−kΔs−q(Δs)^3
work done = Force x displacement

limits are x = 0 to x = 0.15 m
work done

![W = [\dfrac{kx^2}{2}+\dfrac{qx^4}{4}+ C]_0^0.15](https://tex.z-dn.net/?f=W%20%3D%20%5B%5Cdfrac%7Bkx%5E2%7D%7B2%7D%2B%5Cdfrac%7Bqx%5E4%7D%7B4%7D%2B%20C%5D_0%5E0.15)

W = 3.375 + 0.1139
W = 3.3488 J
b) % cubic term =
% cubic term =