The mutual inductance of the two coils is 1.28*10^-3H.
To find the answer, we have to know about the mutual inductance.
<h3>How to find the
mutual inductance of the two coil?</h3>
- We have the expression for emf in terms of mutual inductance and rate of change of current as,
![\epsilon=-M\frac{dI}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%3D-M%5Cfrac%7BdI%7D%7Bdt%7D)
- From the question, it is clear that,
![\epsilon= 9.2*10^{-3}V\\\\\frac{dI}{dt}=-7.2A/s \\\\M=?\\](https://tex.z-dn.net/?f=%5Cepsilon%3D%209.2%2A10%5E%7B-3%7DV%5C%5C%5C%5C%5Cfrac%7BdI%7D%7Bdt%7D%3D-7.2A%2Fs%20%5C%5C%5C%5CM%3D%3F%5C%5C)
- Thus, the mutual inductance is,
![M=-\frac{\epsilon}{(\frac{dI}{dt} )} \\M=-\frac{9.2*10^{-3}}{-7.2} =1.28*10^{-3}H](https://tex.z-dn.net/?f=M%3D-%5Cfrac%7B%5Cepsilon%7D%7B%28%5Cfrac%7BdI%7D%7Bdt%7D%20%29%7D%20%5C%5CM%3D-%5Cfrac%7B9.2%2A10%5E%7B-3%7D%7D%7B-7.2%7D%20%3D1.28%2A10%5E%7B-3%7DH)
Thus, we can conclude that, the mutual inductance of the two coils is 1.28*10^-3H.
Learn more about the mutual inductance here:
brainly.com/question/14305970
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41.2 = h-1/2g(t-1)^2
<span> {-h = -1/2gt^2-1/2g+g*t-41.2
</span><span> {h = 1/2gt^2
</span><span> summing them up
</span><span> 0 = -1/2g+g*t-41.2
</span><span> 41.2 +4.9 = g*t
</span><span> t = 46.1/9.8 = 4.70 sec
</span><span> h = 1/2gt^2 =4.9*(4.70^2) = 108.241 m </span>
<span>B) The period increases and the frequency decreases.
Hope this helps!
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