Which of the following is NOT proof of a chemical change

Physics

2 answers:

Blababa [14]3 years ago

4 0

Answer:

Explanation:

all are proof Eeeeeeeeeee

Zinaida [17]3 years ago

4 0

Answer:

E. ALL ARE PROOF

Explanation:

these are all examples of chemical changes

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When you ride a bicycle, in what direction is the angular velocity of the wheels? When you ride a bicycle, in what direction is

Hitman42 [59]

Complete question is;

When you ride a bicycle, in what direction is the angular velocity of the wheels? A) to your left B) to your right C) forwards D) backwards

Answer:

Option A - to your left

Explanation:

While an object rotates, each particle will have a different velocity:

the 'Speed' component will vary with radius while the 'Direction' component will vary with angle.

All of the velocity vectors are aligned in the same plane.

We can be solve this by choosing a single vector normal to ALL of the possible velocity vectors of the rotating object in that plane.

This convention used is known as "Right-hand rule". The angular velocity vector points along the wheel's axle. For instance, if you Imagine wrapping your right hand around the axle so that your fingers point in the direction of rotation, with your thumb sticking out. You will notice that your thumb points to the left.

Thus;

By right-hand rule, a wheel rotating on a forward - moving bicycle has an angular velocity vector pointing to the rider's left.

So, option A is the correct answer

3 0

4 years ago

A 6.5×10−2 kg arrow hits the target at 25 m/s and penetrates 3.8 cm before stopping.

White raven [17]

1) We use:
2as = v² - u², with v = 0,
to find the acceleration of the arrow.
2 x 0.038 x a = -(25)²
a = -8.22 x 10³ m/s²
F = ma
F = 6.5 x 10⁻² x -8.22 x 10³
F = -534.2 N; the negative direction indicates that the force is in the opposite direction of the motion.

B) The arrows force is the same but in the opposite directioin.
534.2 N

C) a = -8.22 x 10³ m/s²
s = -(65)²/(2 x -8.22 x 10³)
s = 25.7 cm

8 0

3 years ago

A projectile of mass 9.6 kg is launched from the ground with an initial velocity of 12.4 m/s at angle of 54° above the horizonta

Temka [501]

Answer:

The location is at (3.535, 1.162) m

Solution:

As per the question:

Mass of the projectile, m = 9.6 kg

Initial velocity, v = 12.4 m/s

Angle, $\theta = 54^{\circ}$