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Lerok [7]
3 years ago
8

Naturally occurring gallium is a mixture of isotopes

Chemistry
1 answer:
katrin2010 [14]3 years ago
7 0
It is b have a great rest of your day
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Answer the question below ​
goldenfox [79]

Answer:

Be

Explanation:

Reactivity increases from left to right and decreases from the top of the column to the bottom of column

7 0
2 years ago
(pls help)
WITCHER [35]
Anthony’s because it explains way more
8 0
1 year ago
Is cl metal nonmetal or metalloid<br> or metalloid
Korvikt [17]

Answer:

nonmetal

Explanation:

go to ptable.com. it helps a lot

4 0
3 years ago
Write Qc for each of the following:(1) Gaseous sulfur tetrafluoride reacts with liquid water to produce gaseous sulfur dioxide a
snow_tiger [21]

Answer : The expression for reaction quotient will be :

(1) Q_c=\frac{[SO_2][HF]^4}{[SF_4]}

(2) Q_c=\frac{[O_2]^2[Xe]}{[XeF_2]}

Explanation :

Reaction quotient (Q_c) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

(1) The given balanced chemical reaction is,

SF_4(g)+2H_2O(l)\rightarrow SO_2(g)+4HF(g)

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.  So, the expression for reaction quotient will be :

Q_c=\frac{[SO_2][HF]^4}{[SF_4]}

(2) The given balanced chemical reaction is,

2MoO_2(s)+XeF_2(g)\rightarrow 2MoF(l)+Xe(g)+2O_2(g)[/texIn this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.  So, the expression for reaction quotient will be :[tex]Q_c=\frac{[O_2]^2[Xe]}{[XeF_2]}

7 0
3 years ago
A 11.97g sample of NaBr contains 22.34 % Na by mass. Considering the law of constant composition (definite proportions), how man
kap26 [50]
<h3>Answer:</h3>

2.125 g

<h3>Explanation:</h3>

We have;

  • Mass of NaBr sample is 11.97 g
  • % composition by mass of Na in the sample is 22.34%

We are required to determine the mass of 9.51 g of a NaBr sample.

  • Based on the law of of constant composition, a given sample of a compound will always contain the sample percentage composition of a given element.

In this case,

  • A sample of 11.97 g of NaBr contains 22.34% of Na by mass
  • Therefore;

A sample of 9.51 g of NaBr will also contain 22.345 of Na by mass

  • But;

% composition of an element by mass = (Mass of element ÷ mass of the compound) × 100

  • Therefore;

Mass of the element = (% composition of an element × mass of the compound) ÷ 100

Therefore;

Mass of sodium = (22.34% × 9.51 g) ÷ 100

                         = 2.125 g

Thus, the mass of sodium in 9.51 g of NaBr is 2.125 g

3 0
2 years ago
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