The concepts used to solve this exercise are given through the calculation of distances (from the Moon to the earth and vice versa) as well as the gravitational potential energy.
By definition the gravitational potential energy is given by,
Where,
m = Mass of Moon
G = Gravitational Universal Constant
M = Mass of Ocean
r = Radius
First we calculate the mass through the ratio given by density.
PART A) Gravitational potential energy of the Moon–Pacific Ocean system when the Pacific is facing away from the Moon
Now we define the radius at the most distant point
Then the potential energy at this point would be,
PART B) when Earth has rotated so that the Pacific Ocean faces toward the Moon.
At the nearest point we perform the same as the previous process, we calculate the radius
The we calculate the Potential gravitational energy,
Bernoulli's principle describes the relationship between the pressure and the velocity of a moving fluid. It states that as the velocity of the fluid flow increases, the pressure that is exerted decreases.
Answer:
$900
Explanation:
Step 1: Our output value is 9000.
Step 2: We represent the unknown value with x.
Step 3: From step 1 above,$9000=100\%$
Step 4: Similarly, x=10%
Step 5: This results in a pair of simple equations:
$9000=100
Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both
equations have the same unit (%); we have
\frac{9000}{x}=\frac{100\%}{10\%}
Step 7: Again, the reciprocal of both sides gives
\frac{x}{9000}=\frac{10}{100}$
\Rightarrow x=900$
Therefore, $10\%$ of $9000$ is $900$
Answer:
T=21.7 min
Explanation:
The volume of one mole of gas at STP is
22.4 L
10.0 L
then has
n'=10.0/22.4 moles
the total energy released is then
Et= (10.0/22.4)* 286 kJ
Et=127.678 KJ
Power*time = energy, so time = energy/power =
Power=100W
Power=100 J/s
T= 127.6785kJ/100J/s = 1277 sec
T=1276.78sec/60min=21.3 min
Answer:
(a) 391 N
(b) 39.89 kg
(c) 5 m/s^2
Explanation:
Reading of scale when escalator is moving up = 591 N
Reading of scale when escalator is at rest = 391 N
Le a be the acceleration of the escalator.
(a) when the escalator is at rest, it gives the weight of person.
So, mg = 391 N
Thus, the weight of person is 391 N.
(b) Weight = m g
m = Weight / g = 391 / 9.8 = 39.89 kg
Thus, the mass of the person is 39.89 kg.
(c) As it is moving up, by using the Newton's second law
R - mg = m a
591 - 391 = 39.89 a
a = 5 m/s^2
Thus, the acceleration of the elevator is 5 m/s^2.