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Elis [28]
3 years ago
7

The combustion of hydrogen gas releases 286 kJ per mol of hydrogen. If 11.0 L of hydrogen at STP was burned to produce electrici

ty, how long would it power a 100-watt (W) light bulb? Assume no energy is lost to the surroundings. (1 W = 1 J/s)
Physics
1 answer:
Alekssandra [29.7K]3 years ago
8 0

Answer:

T=21.7 min

Explanation:

The volume of one mole of gas at STP is

22.4 L  

10.0 L

then has

n'=10.0/22.4 moles  

the total energy released is then

Et= (10.0/22.4)* 286 kJ  

Et=127.678 KJ

Power*time = energy, so time = energy/power =

Power=100W

Power=100 J/s

T= 127.6785kJ/100J/s = 1277 sec

T=1276.78sec/60min=21.3 min

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What is the impulse of a 2 kg object that starts at 10 m/s and comes to a stop over 0.4 seconds?
gizmo_the_mogwai [7]

Answer: Impulse = 20 Ns

Explanation:

Impulse is the product of force and time

Also impulse = momentum

Where momentum is the product of mass and velocity.

Given that

M = 2kg

V = 10 m/s

Impulse = MV = 2 × 10 = 20 Ns

8 0
3 years ago
Suppose that, while lying on a beach near the equator of a far-off planet watching the sun set over a calm ocean, you start a st
zubka84 [21]

Answer:

R=3818Km

Explanation:

Take a look at the picture. Point A is when you start the stopwatch. Then you stand, the planet rotates an angle α and you are standing at point B.

Since you travel 2π radians in 24H, the angle can be calculated as:

\alpha =\frac{2*\pi *t}{24H}  t being expressed in hours.

\alpha =\frac{2*\pi *11.9s*1H/3600s}{24H}=0.000865rad

From the triangle formed by A,B and the center of the planet, we know that:

cos(\alpha )=\frac{r}{r+H}  Solving for r, we get:

r=\frac{H*cos(\alpha) }{1-cos(\alpha) } =3818Km

6 0
3 years ago
How many seconds are there in 13 hours?
Zina [86]

Answer:

46,800 seconds. I hope this helps

7 0
3 years ago
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Make a report on the different types of effects of forces acting on an object
frez [133]

Explanation:

According to newtons first law of motion " A body is at a state of rest or uniform motion unless acted upon by a force (external)" which will either

1. change the direction

2. change the acceleration

3. change the velocity(moves or stop the body from moving)

4. change the shape or size

8 0
4 years ago
ASAP please!! <br>The force vectors on an aircraft are as shown. Find the net (resultant force).
ioda

Answer:

The magnitude of the net force is 5430N

Explanation:

I suggest to define the axes as aligned to the axis of the plane. This will require you to decompose only one vector, namely the Weight. We need two components of the W force: one in horizontal direction of the plane, the other perpendicular to it. Through a simple triangle argument you will se that the plane-horizontal component of W is

W_D=3600 N\cdot\sin 27^\circ=1634N

acting in the direction of the Drag, and the plane-perpendicular component is:

W_L=-3600N\cdot\cos 27^\circ=-3208N

with negative sign since it counteracts the Lift.

So the components of the netforce F are:

F_h=T-D-W_D=(8000-1000-1634)N=5366N\\F_v=L+W_L=(4100-3208)N=829N

The magnitude of the  net force is:

|F|=\sqrt{5366^2+829^2}N = 5430N


6 0
3 years ago
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