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lara [203]
3 years ago
15

HELP

Chemistry
1 answer:
Natalka [10]3 years ago
3 0

Explanation:

To find the amount of product that would be formed from two or more reactants, we need to follow the following steps;

  • Find the number of moles of the given reactants.
  • Then proceed to determine the limiting reactant. The limiting reactant is the one in short supply which determines the extent of the reaction.
  • Use the number of moles of the limiting reactant to find the number of moles of the product.
  • Then use this number of moles to find the mass of the product

Useful expression:

    Mass   =  number of moles x molar mass

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What type of wave needs molecules in order to transfer the energy.
ratelena [41]
The answer is heat waves
6 0
3 years ago
The equilibrium constant for the reaction of carbon monoxide with water is 1.845. if 1.00 mol of each reactant is placed in a 2.
SpyIntel [72]
[CO] = 1 mol / 2L = 0.5 M

[
According to the equation:

and by using the ICE table:

             CO(g) + H2O(g) ↔   CO2(g) + H2(g)

initial     0.5            0.5                    0          0

change  -X              -X                   +X         +X
     
Equ       (0.5-X)       (0.5-X)                     X            X

when Kc = X^2 * (0.5-X)^2

by substitution:

1.845 = X^2 * (0.5-X)^2  by solving for X 

∴X = 0.26

∴ [CO2] = X = 0.26
4 0
3 years ago
Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it
lions [1.4K]

<u>Answer:</u> The equilibrium concentration of COF_2 is 0.332 M

<u>Explanation:</u>

We are given:

Initial concentration of COF_2 = 2.00 M

The given chemical equation follows:

                2COF_2(g)\rightleftharpoons CO_2(g)+CF_4(g)

<u>Initial:</u>          2.00

<u>At eqllm:</u>     2.00-2x          x      x

The expression of K_c for above equation follows:

K_c=\frac{[CO_2][CF_4]}{[COF_2]^2}

We are given:

K_c=6.30

Putting values in above expression, we get:

6.30=\frac{x\times x}{(2.00-2x)^2}\\\\x=0.834,1.25

Neglecting the value of x = 1.25 because equilibrium concentration of the reactant will becomes negative, which is not possible

So, equilibrium concentration of COF_2=(2.00-2x)=[2.00-(2\times 0.834)]=0.332M

Hence, the equilibrium concentration of COF_2 is 0.332 M

4 0
3 years ago
If
defon

Answer:

If

0.0357

mol

CaCl

2

is dissolved in water to make a

0.420

M

solution, what is the volume of the solution?

4 0
3 years ago
Space exploration was aided most by the
densk [106]

Explanation:

Space exploration was aided most by the use of liquid fuel.

<em>Hope</em><em> </em><em>this helps</em><em>.</em><em>.</em><em> </em>

3 0
3 years ago
Read 2 more answers
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