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3 years ago

Which layer of ground contains organic matter and tiny rock particles?

Chemistry

1 answer:

Ann [662]3 years ago

4 0

Answer:

A Horizon - The layer called topsoil; it is found below the O horizon and above the E horizon. Seeds germinate and plant roots grow in this dark-colored layer. It is made up of humus (decomposed organic matter) mixed with mineral particles.

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Name the two products when calcium carbonate (CaCO3) is heated

trapecia [35]

Answer:

The products are Calcium oxide and Carbon dioxide.

Explanation:

When calcium carbonate is heated, thermal decomposition occurs.

Calcium calcium → Calcium oxide + Carbon dioxide

3 0

3 years ago

Read 2 more answers

Think about agriculture research which of the following statements is accurate?

irina [24]

A.genetic modification of food helps it grow more easily in certain areas

Explanation:

The statement genetic modification of food helps it grow more easily in certain areas is a form of agricultural research that is very accurate.

Genetically modifying food is common practice in order to encourage desirable and sustainable traits in plant species.

Drought resistant breeds can tolerate a much lower level of water in some specific areas.
Disease resistant breeds are more adapted to outbreaks of plant epidemics.
Overall, genetic modification of food helps them to grow and produce better.

learn more:

Genetic recombination brainly.com/question/12685192

#learnwithBrainly

4 0

3 years ago

HELP! ME! PLEASE!

tankabanditka [31]

Answer:

Explanation:

Magnetism or magnetic field lines move through just about anything. The earth somehow creates a magnet near it"s center and these magnetic field lines move through the lava, rock, and soil of the earth to control a compass on the surface. So moving through a piece of cardboard is no problem for magnetism.

7 0

2 years ago

Help please !!!!!!!!

Elena L [17]

Answer:

Option B. 2096.1 K

Explanation:

Data obtained from the question include the following:

Enthalpy (H) = +1287 kJmol¯¹ = +1287000 Jmol¯¹

Entropy (S) = +614 JK¯¹mol¯¹

Temperature (T) =.?

Entropy is related to enthalphy and temperature by the following equation:

Change in entropy (ΔS) = change in enthalphy (ΔH) / Temperature (T)

ΔS = ΔH / T

With the above formula, we can obtain the temperature at which the reaction will be feasible as follow:

ΔS = ΔH / T

614 = 1287000/ T

Cross multiply

614 x T = 1287000

Divide both side by 614

T = 1287000/614

T = 2096.1 K

Therefore, the temperature at which the reaction will be feasible is 2096.1 K

5 0

3 years ago

The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that

kakasveta [241]

The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is $1.1\times 10^6$ M.

$HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)$

This value indicates that

A. $CN^-$ is a stronger base than $ONO^-$

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is $ONO^-$

D. The conjugate acid of CN- is HCN

Answer: A. $CN^-$ is a stronger base than $ONO^-$

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When $K_{p}>1$ ; the reaction is product favoured.

When $K_{p};$ ; the reaction is reactant favored.

$When K_{p}=1$ ; the reaction is in equilibrium.

As, $K_p>>1$ , the reaction will be product favoured and as it is a acid base reaction where $HONO$ acts as acid by donating $H^+$ ions and $CN^-$ acts as base by accepting $H^+$

Thus $HONO$ is a strong acid thus $ONO^-$ will be a weak conjugate base and $CN^-$ is a strong base which has weak $HCN$ conjugate acid.

Thus the high value of K indicates that $CN^-$ is a stronger base than $ONO^-$

7 0

3 years ago