1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tomtit [17]
3 years ago
7

The nucleus of an atom is dense and positively charged. What was observed when positively charged particles were radiated onto a

gold atom during Rutherford's experiment because of this?
Negative charges were concentrated at the center of the atom.
Particles that struck the center of the atom were repelled.
Particles that struck the edges of the atom were repelled.
Positive charges were distributed all over the atom.
Chemistry
2 answers:
Alex_Xolod [135]3 years ago
8 0
Not sure but i think c Particles that struck the edges.

My best guess
san4es73 [151]3 years ago
6 0

Answer:

Particles that struck the center of the atom were repelled.

Explanation:

In 1911, New Zealand physicist Ernest Rutherford carried out an experiment in order to deepen his knowledge of the atomic model hitherto adopted, which was that of Thomson; in which the atom would be a sphere of positive, non-massive electrical charge, encrusted with (negative) electrons, so that its total electrical charge would be zero.

To carry out such an experiment he bombed a very thin gold leaf (thickness of approximately 10-4 mm), through a beam of alpha particles (α), coming from a sample of polonium. The polonium was inside a lead block, with an orifice, through which only the emissions of alpha particles would be allowed out.

In addition, lead plates with holes were placed in their centers, which would orient the beam towards the gold blade. And, finally, a bulkhead covered with zinc sulfide, which is a fluorescent substance, was placed behind the slide, where it was possible to visualize the path taken by the alpha particles.

At the end of this experiment, Rutherford noticed that most of the alpha particles passed through the slide, did not deflect or retreat. Some alpha particles deflected, and very few receded. In addition, the particles that reached the center of the atom were repelled.

Based on these data, Rutherford concluded that, contrary to what Dalton thought, the atom could not be massive. But in reality, much of the atom would be empty and it would contain a very small, dense and positive nucleus.

You might be interested in
In the following take CV = 20.8 and CP = 29.1 J⋅mol−1⋅°C−1 for nitrogen gas: (a) Three moles of nitrogen at 30°C, contained in a
vagabundo [1.1K]

Answer:

224 \times 13313\frac{.131?}{?244}

4 0
3 years ago
During which process of the water cycle do water molecules absorb a great amount of solar energy? A. evaporation B. condensation
jolli1 [7]

When a man cumxs on a girls face, lets it dry, then peels it off and feeds it to her. This is called a mexican pancake

3 0
3 years ago
Why does a pan of warm water eventually become the same temperature as the room it is in
rewona [7]
the room will either cool down or warm up the water until it is the same temperature as the room around it.
4 0
3 years ago
Will give brainliest if you show work and have the right answer :)
suter [353]

Answer:

The answer to your question is:

a) 36 g of water

Explanation:

MW SO₂ = 32 + 32 = 64 g

MW Br = 80 g

MW H₂O = 18 g

MW HBr = 81 g

MW H₂SO₄ = 98

Balanced reaction:

                      SO₂   +   2Br   +   2H₂O    ⇒    2HBr   +   H₂SO₄

                     64g       2(80)        2(18)             2(81)            98

                     64.1       159.9                           161.9             98.1

Rule of three with Br and H2O

                              160 g ----------------   36 g

                              160 -------------------    x

           x = 160(36)/160 = 36 g oh water

                   

4 0
4 years ago
Read 2 more answers
If 4.35 grams of zinc metal react with 35.8 grams of silver nitrate, how many grams of silver metal can be formed and how many g
vaieri [72.5K]
The balanced chemical reaction is written as:

<span>Zn + 2AgNO3 = Zn(NO3)2 + 2Ag

To determine the grams of silver metal that is being produced, it is important to first determine which is the limiting reactant and the excess reactant from the given initial amounts. We do as follows:

4.35 g Zn ( 1 mol / 65.38 g ) ( 2 mol AgNO3 / 1 mol Zn ) = 0.1331 mol AgNO3 needed
35.8 g AgNO3 ( 1 mol / 169.87 g ) ( 1 mol Zn / 2 mol AgNO3 ) = 0.1054 mol Zn needed

Therefore, the limiting reactant would be the zinc metal since it would be consumed completely in the reaction. The excess amount of AgNO3 would be:

0.2107 mol AgNO3 - 0.1331 mol AgNO3 = 0.0776 mol AgNO3 left ( 169.87 g / 1 mol ) = 13.19 g AgNO3 left

0.0665 mol Zn ( 2 mol Ag / 1 mol Zn) ( 107.9 g / 1 mol) = 14.3581 g Ag produced</span>
5 0
4 years ago
Other questions:
  • What structural units make up network solids
    6·1 answer
  • What is the length of the hypotenuse x if (12,35,x) is a Pythagorean triple
    6·2 answers
  • If the mass of a material is 43 grams and the volume of the material is 9 cm^3, what would the density of the material be?
    5·1 answer
  • The pressure of a 609.64 gram sample of F2 in a 88.84 L container is measured to be 2770.96 torr. What is the temperature of thi
    9·1 answer
  • How much H2O is produced when 20000 g of C2H2 burns completely? Answer in units of g.
    12·1 answer
  • The average atomic mass of a sample of an element X is 16.2u. What are the percentages of isotopes X (mass number 16, atomic num
    15·1 answer
  • When baking soda and vinegar react to certain surfaces up bubbles what does this mostly indicate
    10·1 answer
  • Where are people exposed to chemicals?
    5·1 answer
  • The saturation point for a solution is 50.0 grams of solute per 500 grams of solvent. How many grams of solute can be dissolved
    5·1 answer
  • Question
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!