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Virty [35]
3 years ago
10

A spring has an unstretched length of 16 cm . A 110 g mass hanging from the spring stretches it to an equilibrium length of 24 c

m . Part APart complete Suppose the mass is pulled down to where the spring's length is 32 cm . When it is released, it begins to oscillate. What is the amplitude of the oscillation
Physics
1 answer:
Jet001 [13]3 years ago
7 0

Answer:

the amplitude of the oscillation is 8 cm

Explanation:

The computation of the amplitude of the oscillation is shown below:

= Length of the spring - length of the equilibrium

= 32 cm - 24 cm

= 8 cm

By deducting the  length of the equilibrium from the length of the spring we can get the amplitude of the oscillation and the same is to be considered

hence, the amplitude of the oscillation is 8 cm

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a) vf = vi + at

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A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.
MakcuM [25]

Answer:

b. 9.5°C

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m_i = Mass of ice = 50 g

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The equation of the system's heat exchange is given by

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4 0
3 years ago
Two 2.0cm×2.0cm metal electrodes are spaced 1.0 mm apart and connected by wires to the terminals of a 9.0 v battery. What is the
Fantom [35]

Answer:

The charge on each electrode is

q=0.354 x10^{-12}

Explanation:

The charge to find the equation is development

V=9v

d=1.0 mm\\A=2cm*2cm=0.02m*0.02m\\A=4x10^{-4} \\E_{o} =8.85x10^{-12} (\frac{C^{2} }{N*m^{2} } )

q=C*V

C=\frac{E_{o}*A }{d} \\C=\frac{8.85x10^{-12} *4x10^{-4}  }{0.01}=0.354  \\

q=0.354*9v\\q=3.186x10^{-12} C

3 0
4 years ago
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