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3 years ago

Someone plzzz help it’s my test it’s 50 summative points I’ll mean a lot of you can help thank youuu!!

Physics

2 answers:

DaniilM [7]3 years ago

8 0

Answer:if you go to g○○gle there's a camera icon next to the search bar, click on that and take a photo of your test, then they'll find the answers that other people answered or needed, hope that helps

Explanation:

Greeley [361]3 years ago

4 0

These are the answers 1) d
2)b
3)a
4)c
5)a
6)b

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a high speed train travels with an average speed of 250 km/h. the train travels for 2 hrs. how far does the train travel

steposvetlana [31]

Answer:

<h3>The answer is 500 km </h3>

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

<h3>distance = average velocity × time</h3>

From the question

average speed = 250 km/h

time = 2 hrs

We have

distance = 250 × 2

We have the final answer as

Hope this helps you

5 0

3 years ago

Read 2 more answers

A small metal bead, labeled A, has a charge of 26 nC . It is touched to metal bead B, initially neutral, so that the two beads s

adell [148]

Answer:

$q_A=25.953\ \rm nC$

$q_B=0.047\ \rm nC$

Explanation:

Given:

Total initial charge on bead A=26 nC
The distance between them=5 cm
Magnitude o the force between them $=4.4\times10^{-4}$

Using coulombs law the force between two charged particle is $\dfrac{q_Aq_B}{4\pi \epsilon_0 r^2}$

where r is the radial distance between them

According to question we have

$4.4\times10^{-4}=\dfrac{q_Aq_B\times9\times10^9}{0.05^2}\\\\4.4\times10^{-4}=\dfrac{q_A(q_A-26\times10^{-9})\times9\times10^9}{0.05^2}\\q_A=25.953\ \rm nC\\q_B=0.047\ \rm nC$

Hence the charge on two metal beads is calculated.

5 0

3 years ago

Which example best

Snezhnost [94]

Answer:

Explanation:

paddling a canoe to make the boat move

7 0

3 years ago

Two parallel plates 19 cm on a side are given equal and opposite charges of magnitude 2.0 ✕ 10^−9 C. The plates are 1.8 mm apart

Romashka [77]

Answer:

E = 5291.00 N/C

Explanation:

Expression for capacitance is

$C = \frac{\epsilon A}{d}$

where

A is area of square plate

D = DISTANCE BETWEEN THE PLATE

$C = \frac{\epsilon\times(19\times 10^{-2})^2}{1.5\times 10^{-3}}$

$C = 24.06 \epsilon$

$C = 24.06\times 8.854\times 10^{-12} F$

$C =2.1\times 10^{-10} F$

We know that capacitrnce and charge is related as

$V = \frac{Q}{C}$

$= \frac{2\tiimes 10^{-9}}{2.\times 10^{-10}}$

v = 9.523 V

Electric field is given as

$E = \frac{V}{d}$

= $\frac{9.52}{1.8*10^{-3}}$

E = 5291.00 V/m

E = 5291.00 N/C

5 0

3 years ago

HELP NEEDED! Determine the mechanical energy of this object: a 1-kg ball rolls on the ground at 2 m/s.

valentina_108 [34]

The mechanical energy of an object is the sum of its potential and kinetic energy.

Because the ball is on the ground, its potential energy is 0.
Its kinetic energy is given by:

K.E = 1/2 mv²
K.E = 1/2 x 1 x 2²
K.E = 2 J

Mechanical energy = 2 + 0
Mechanical energy = 2 J

The answer is B.

4 0

4 years ago

Read 2 more answers