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Oksana_A [137]
3 years ago
14

Lin runs 5 laps around a track in 15 minutes. How many minutes is per lap is that?

Mathematics
2 answers:
muminat3 years ago
8 0

Answer:

3 min per lap

Step-by-step explanation:

15 (minutes)/5 (lap)= 3 minutes

Ket [755]3 years ago
7 0

Answer:3 minutes per lap

Step-by-step explanation:

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An aquarium is being filled at a rate of 2.5 inches per second. The equationLaTeX: y=2.5xy = 2.5 x is used to determine the heig
Reika [66]

Answer:

Step-by-step explanation:

Given the equation y = 2,5x

y is the height of the water

x is the time.

To get the range of values of the height at t = 60s, we will substitute x = 60 into the function

y = 2.5(60)

y = 150 in

Hence the range of the situation is [0, 150].

The domain will be all positive integers i.e xEZ

3 0
3 years ago
Delta Math! Please help.
vodka [1.7K]

Answer:

x = 1.5\sqrt{3}

Step-by-step explanation:

using the sine ratio in the right triangle and the exact value

sin60° = \frac{\sqrt{3} }{2} , then

sin60° = \frac{opposite}{hypotenuse} = \frac{x}{3} = \frac{\sqrt{3} }{2} ( cross- multiply )

2x = 3\sqrt{3} ( divide both sides by 2 )

x = 1.5\sqrt{3}

6 0
2 years ago
Read 2 more answers
9 inches of ribbon are needed for wrapping each present. How many presents can be wrapped with 6 yards of ribbon?
netineya [11]

Answer:

a total of 24 presents can be wrapped

Step-by-step explanation:

6 x 3 = 18 feet of ribbon

18 x 12 = 216 inches of ribbon

216/9 = 24 presents can be wrapped

3 0
3 years ago
Drag each number to the correct location on the equations. Each number can be used more than once, but not all numbers will be u
7nadin3 [17]

The system of equations to find the cost of one adult ticket, a, and the cost of one child ticket, c are Roy's; 6a+2c=66 Elisa's 5a+4c=62.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Let's consider adults tickets be a and child tickets be c

so

Roy's purchase

6a+2c=66------1

Elisa's purchase

5a+4c=62-------2

Hence,  the system of equations

6a+2c=66------1

5a+4c=62-------2

solving simultaneously

6a+2c=66

5a+4c=62

Also,

 12a+4c=132

-5a+4c=62

  7a=70

a=$10

put  a=70 in 1

6(10)+2c=66

60+2c=66

2c=66-60

2c=6

c=$3

Learn more about equations here;

brainly.com/question/10413253

#SPJ1

4 0
1 year ago
Does anyone know how to solve a system of linear equations using elimination? I am having a hard time on how to do it for differ
Mariana [72]
1. Multiply each equation so they end up with the same coefficient

2. Subtract your second equation from the first

3. Solve for one of the variables (I tend to solve an equation that only contains 2 variables if possible. So it would be if you have one question with x and y, solve for the easier one)

4. Substitute the variable you found in the least step into one of the other equations and find a second variable.

5. Substitute both variables you found into the last equation and there you should be left with x, y, and z :))

I hope this helped sksjsk if it didn’t I could write it out to hopefully help more :)
3 0
3 years ago
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