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Oksana_A [137]
2 years ago
14

Lin runs 5 laps around a track in 15 minutes. How many minutes is per lap is that?

Mathematics
2 answers:
muminat2 years ago
8 0

Answer:

3 min per lap

Step-by-step explanation:

15 (minutes)/5 (lap)= 3 minutes

Ket [755]2 years ago
7 0

Answer:3 minutes per lap

Step-by-step explanation:

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4. Which expression represents "4 less than the product of 2 and a number e"?
frutty [35]
The answer for this problem is c bc that’s what I think
3 0
3 years ago
Which value of x makes 7+5(×-3)=22
Arlecino [84]

Answer:

x=6

Step-by-step explanation:

7+5(×-3)=22

expand the brackets:

7 + 5x - 15 = 22

simplify:

5x - 8 = 22

add 8 to both sides:

5x = 30

divide both sides by 5

x = 6

hope this helps

brainliest plz?

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8 0
3 years ago
Read 2 more answers
A cylinder has a base radius of 6m and a height of 16m. What is its volume in cubic m,
SpyIntel [72]

Answer:

To the nearest tenth place, V = 1,810.3 m^3

Step-by-step explanation:

In this question, we are tasked with calculating the volume of a cylinder given its base radius and height.

Mathematically, the Volume can be calculated using the formula

V = pi * r^2 * h

where pi = 22/7 , r = 6m and h = 16m

Plugging these values, we have

V = 22/7 * 6^2 * 16

V = 22/7 * 36 * 16

V = 1,810.286 m^3

To the nearest tenth place, V = 1,810.3 m^3

8 0
3 years ago
7(2x+6)=1 plzzz Yelp
Ierofanga [76]

Answer:

x=-\dfrac{41}{14}

Step-by-step explanation:

7(2x+6)=1

Expand parentheses:

14x+42=1

Subtract 42 from both sides:

14x=-41

Divide both sides by 14:

x=-\dfrac{41}{14}

Hope this helps!

4 0
2 years ago
Read 2 more answers
Problem 1.(32 points) A random sample of 100 Uber rides in Chicago has on average 5.4miles per ride. Assume the distribution of
marshall27 [118]

Answer:

a) CI = ( 5,1 ; 5,7 )

b) SE =  0,1  

Step-by-step explanation:

a) Sample random     n  = 100

Mean  =  μ = 5,4

Standard deviation   s = 1,3

CI = 99 %    α = 1 %   α = 0,01     α/2 =  0,005

z(c) for  0,005 is from z-table    z(c)  = 2,575

z(c)  =  ( X - μ ) /s/√n          CI  =  μ ± z(c) * s/√n

CI =  5,4 ± 2,575* 1,3/10

CI = 5,4 ± 0,334

CI = ( 5,1 ; 5,7 )

b) SE = Standard deviation / √n

SE = 1,3 /10       SE =  0,1  

We can support that with 99 % of probability our random variable will be in the CI.

6 0
2 years ago
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