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Oksana_A [137]
3 years ago
14

Lin runs 5 laps around a track in 15 minutes. How many minutes is per lap is that?

Mathematics
2 answers:
muminat3 years ago
8 0

Answer:

3 min per lap

Step-by-step explanation:

15 (minutes)/5 (lap)= 3 minutes

Ket [755]3 years ago
7 0

Answer:3 minutes per lap

Step-by-step explanation:

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Nonamiya [84]

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Step-by-step explanation:

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3 years ago
Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following: 18 Pennies13 Dimes 18 Nickels1
Nezavi [6.7K]

Answer:

P(Nickel\ and\ Nickel) = 0.08091

Step-by-step explanation:

Given

Pennies = 18

Dimes = 13

Nickels = 18

Quarters = 13

Required

Probability of selecting 2 nickels without replacement

This can be represented as: P(Nickel\ and\ Nickel)

The solution is as follows

P(Nickel\ and\ Nickel) = \frac{Nickel}{Total}*\frac{Nickel-1}{Total-1}

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So, we have:

P(Nickel\ and\ Nickel) = \frac{18}{62}*\frac{18-1}{62-1}

P(Nickel\ and\ Nickel) = \frac{18}{62}*\frac{17}{61}

P(Nickel\ and\ Nickel) = \frac{18*17}{62*61}

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P(Nickel\ and\ Nickel) = 0.08091

6 0
3 years ago
Find the length of each diagnol and the area
katrin [286]

Answer:

The length of diagonal BD is 11·(1 + √3)

The length of diagonal AC = 22

Step-by-step explanation:

The given data are;

Quadrilateral ABCD = A kite

The length of segment AD = 22

The measure of ∠DAE = 60°

The measure of ∠BCEE = 45°

Whereby, triangle ΔADE = A right triangle, and DE is the perpendicular bisector of AC, by trigonometric ratio, we have;

AE = EC

DE = 22 × sin(60°) = 11·√3

AE = 22 × cos(60°) = 11

∴ AE = EC = 11

BE = EC × tan(∠BCE) = 11 × tan(45°) = 11

The length of the diagonal BD = BE + DE (By segment addition property)

∴ BD = 11 + 11·√3 = 11·(1 + √3)

The length of diagonal BD = 11·(1 + √3)

The length of diagonal AC = AE  + EC

∴ AC + 11 + 11 = 22

The length of diagonal AC = 22.

7 0
3 years ago
What is the middle 50% of data called? *<br><br> Range<br> Interquartile range<br> Median<br> Mean
xeze [42]

Answer:

Step-by-step explanation:

5 0
3 years ago
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