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taurus [48]
3 years ago
10

The water hyacinth lives in lakes and ponds it forms large floating mats of plants because it does not root in soil which adapta

tion lets it get nutrients directly from the water is it A.1 curly leaves B.Trailing C.Sturdy stems D. Upright flowers
Physics
1 answer:
HACTEHA [7]3 years ago
6 0

Answer:

C. Sturdy stems

Explanation:

Sturdy stems is the adaptation that enables water hyacinth to get nutrients directly from the water because there is no roots are present for the absorption of nutrients from water. The hollow bulbous stem below each leaf of water hyacinth allows the plant to get nutrients from the water. This hollow bulbous stem allow the plants to float on the water surface, keeping the leaves and flowers above the water so they don't rot.

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A particle of mass 3m is located 1.00 m from a particle of mass m. (a) Where should you put a third mass M so that the net gravi
Airida [17]

Explanation:

It is given that net gravitational force on M is exactly equal to zero. Hence, distance to M from the bigger mass is 3m. Therefore, expression for net force will be as follows.

           F_{net} = F_{1} + F_{2} = 0  

So,  

          \frac{-G(3m)(M)}{x^{2}} + \frac{G(m)(M)}{(1 - x)^{2}} = 0

The first term is negative as the third mass is located between the other two masses. This means that 3 m will be pulling it leftwards (negative x direction) and m will be pulling it rightwards (positive x direction).

      \frac{G(m)(M)}{(1 - x)^{2}} = \frac{G(3m)(M)}{(x)^{2}}

On dividing both sides of the equation by G.m.M, we get the following.

      \frac{1}{(1 - x)^{2}} = \frac{3}{x^{2}}

               x^{2} = 3 - 6x + 3x^{2}

                    0 = 3 - 6x + 2x^{2}

Using the formula, \frac{-b \pm \sqrt{(b)^{2} - 4ac}}{2a}   the value of x comes out to be equal to +2.37 (not usabale) and -0.634 (usable).

Hence, we can conclude that the third mass will be located 0.634 meters away from the 3 m mass.

7 0
3 years ago
A 0.0434-m3 container is initially evacuated. Then, 4.19 g of water is placed in the container, and, after some time, all of the
adell [148]

Answer:

P =18760.5 Pa

Explanation:

Given that

Volume ,V= 0.0434 m³

Mass ,m= 4.19 g = 0.00419 kg

T= 417 K

If we assume that water vapor is behaving like a ideal gas ,then we can use ideal gas equation

Ideal gas equation    P V = m R T

p=Pressure ,V = Volume ,m =mass

T=Temperature ,R=Universal gas constant

Now by putting the values

P V = m R T

For water R= 0.466 KJ/kgK

P x 0.0434 = 0.00419 x 0.466 x 417

P =18.7605 KPa

P =18760.5 Pa

Therefore the answer is 18760.5 Pa

6 0
4 years ago
The doctor writes a prescription for na heparin 20,000 units in 500 ml n.s. infuse over 8 hours. what is the flow rate in ml/hr?
Ne4ueva [31]
I think this type of equation could be conducted in simple division equation since it does not involve drop rate.

we know that there is 500 ml of substance and should be infused within 8 hours period.

So the flow rate in ml/hr would be: 

500/8 = 62.5 ml/hr                                                                                    
8 0
3 years ago
You are working in a shoe test laboratory measuring the coefficients of friction for running shoes on a variety of surfaces. The
AnnZ [28]

Answer:

0.75

Explanation:

Since the static frictional force is the maximum force applied just before sliding, our frictional force, F is 300 N.

Since F = μN where μ = coefficient of static friction and N = normal force = 400 N (which is the downward force applied against the surface).

So, μ = F/N

= 300 N/400 N

= 3/4

= 0.75

So, the  coefficient of static friction μ = 0.75

6 0
3 years ago
What is the strength of an electric field that will balance the weight of a 3.3 g plastic sphere that has been charged to -7.6 n
sp2606 [1]

As the plastic sphere is charged, therefore it experience an electric force when placed in an electric fields and also experiences gravitational force acts downward so the electric force must act upward.

Let  F_{E} is electric force and F_{G} is gravitational force.

If these forces are balanced, thereforeF_{E} = F_{G}

or                                                                      \left | q \right |E=mg\\\\\ E=\frac{mg}{\left | q \right |}

Given, q=-7.6 nC=-7.6\times10^{-9} C and  m=3.3 g= 3.3\times10^{-3} kg.

Substituting these values in above equation we get,

E=\frac{3.3\times10^{-3} kg\times9.8 m/s^{2} }{7.6\times10^{-9} C}\\\\E=4.2\times10^{6} N/C

Thus, the magnitude of electric field is 4.2\times10^{6} N/C.

As the charge is negative, the electric field at the location of the plastic sphere must be pointing downward.



8 0
3 years ago
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