When a phosphate group is added to a molecule, that molecule is said to have been? The answer is <span>phosphorylation</span>
Answer:
70.34 litres
Explanation:
Using ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the information given in the question;
n = 3 moles
V = ?
P = 105.2 KPa = 105.2/101 = 1.04atm
T = 24.0°C = 24 + 273 = 297K
Using PV = nRT
1.04 × V = 3 × 0.0821 × 297
1.04V = 73.15
V = 73.15 ÷ 1.04
V = 70.34 litres.
It is advisable to wear long sleeve when when a student is working in a chemistry lab so that to protect arms from lab chemicals. when someone enter the chemistry lab to wort or to study should be well prepared with appropriate gears and security measure to avoid injury.
The molar mass of this compound is 0.004 m/g
Firstly, molar mass is moles/grams so we need to solve for the number of moles and we were already given the grams (205 g).
So to solve for moles we were given 205 g, 20.0 L, 273 K and 1.00 atm. Knowing these numbers we can plug them into the ideal gas law, PV=nRT
where P is pressure, V is volume, n is number of moles, R is the gas constant (in this case it is 0.08206) and T is the temperature.
Next, we use moles and grams to solve for molar mass: