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3 years ago

Types of molecular forces

Chemistry

2 answers:

s2008m [1.1K]3 years ago

8 0

Answer:

Hydrogen bonds

Covalent bonds

Van Der Walls Forces

Ionic Bonding

London Dispersion forces

Metallic bonding

Chemical bonds

Pavlova-9 [17]3 years ago

7 0

Mark Brainliest please

Answer:

1. Ionic forces
a. Ion to ion forces
b. Ion to induced dipole

2. Dipole - Dipole forces
a. Hydrogen bonding
b. Keesom (permanent dipole-permanent dipole) interactions
c. Debye (permanent dipole-induced dipole) interactions

3. Van-der-Vaals forces (induced dipole to induced dipole).

Explanation : see the pic for more details

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3 years ago

The rate constant for the reaction 3A equals 4b is 6.00×10 how long will it take the concentration of a to drop from 0.75 to 0.2

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This question is incomplete, the complete question is;

The rate constant for the reaction 3A equals 4B is 6.00 × 10⁻³ L.mol⁻¹min⁻¹.

how long will it take the concentration of A to drop from 0.75 to 0.25M ?

from the unit of the rate constant we know it is a second reaction order

OPTIONS

a) 2.2×10^−3 min

b) 5.5×10^−3 min

c) 180 min

d) 440 min

e) 5.0×10^2 min

Answer:

it will take 440 min for the concentration of A to drop from 0.75 to 0.25M

Option d) 440 min is the correct answer

Explanation:

Given that;

Rate constant K = 6.00 × 10⁻³ L.mol⁻¹min⁻¹

3A → 4B

given that it is a second reaction order;

k = 1/t [ 1/A - 1/A₀]

kt = [ 1/A - 1/A₀]

t = [ 1/A - 1/A₀] / k

K is the rate constant(6.00 × 10⁻³)

A₀ is initial concentration( 0.75 )

A is final concentration(0.25)

t is time required = ?

so we substitute our values into the equation

t = [ (1/0.25) - (1/0.75)] / (6.00 × 10⁻³)

t = 2.6666 / (6.00 × 10⁻³)

t = 444.34 ≈ 440 min {significant figures}

Therefore it will take 440 min for the concentration of A to drop from 0.75 to 0.25M

Option d) 440 min is the correct answer

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3 years ago

Types of molecular forces ​

Types of molecular forces