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kiruha [24]
3 years ago
10

Yo please help I will give you 10 points PLEASE

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
6 0

Answer:

<h3>DEPENDENT VARIABLE</h3>

Explanation:

I HOPE IT HELPS :)

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Heat flows naturally from objects that have higher energy to those with?
Vlad [161]

Answer:

heat flow

Explanation:

heat flow moves to a higher temperature to a lower temperature

8 0
3 years ago
Which factors influence the salinity of ocean surface water?
In-s [12.5K]
C and D

surface water is evaporated by the sun and concentrated the ocean salt and oceans are diluted when rivers flow into them
4 0
3 years ago
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It has been suggested that the surface melting of ice plays a role in enabling speed skaters to achieve peak performance. Carry
vesna_86 [32]

Explanation:

Relation between pressure, latent heat of fusion, and change in volume is as follows.

          \frac{dP}{dT} = \frac{L}{T \times \Delta V}

Also, \frac{L}{T} = \Delta S^{fusion}_{m}

where, \Delta V^{fusion}_{m} is the difference in specific volumes.

Hence,    \frac{dP}{dT} = \frac{\Delta S^{fusion}_{m}}{\Delta V^{fusion}_{m}}

As, \Delta S^{fusion}_{m} = \frac{L}{T} = \frac{6010}{273.15} = 22.0 J/mol K

And,   \Delta V^{fusion}_{m} = \frac{M}{d_{H_{2}O}} - \frac{M}{d_{ice}} ...... (1)

where,    d_{H_{2}O} = density of water

              d_{ice} = density of ice

             M = molar mass of water = 18.02 \times 10^{-3} kg

Therefore, using formula in equation (1) we will calculate the volume of fusion as follows.

        \Delta V^{fusion}_{m} = \frac{M}{d_{H_{2}O}} - \frac{M}{d_{ice}}

                       = \frac{18.02 \times 10^{-3}}{997} - \frac{18.02 \times 10^{-3}}{920}  

                       = -1.51 \times 10^{-6}        

Therefore, calculate the required pressure as follows.

              \frac{dP}{dT} = \frac{22}{-1.51 \times 10^{-6}}

                              = 1.45 \times 10^{7} Pa/K

or,                           = 145 bar/K

Hence, for change of 1 degree pressure the decrease is 145 bar  and for 4.7 degree change dP = 145 \times 4.7 bar

                              = 681.5 bar

Thus, we can conclude that pressure should be increased by 681.5 bar to cause 4.7 degree change in melting point.

5 0
3 years ago
The solubility of copper chloride at 20 °C is 73 g/100 g of water. Kiera adds 100 g of copper chloride to 100 g of water and sti
OLEGan [10]

Answer:

m_{undissolved}=27g

Explanation:

Hello there!

In this case, according to the given information of the solubility of copper chloride, as the maximum amount of this salt one can dissolve without having a precipitate, we infer that since just 73 grams are actually dissolved, the following amount will remain solid as a precipitate:

m_{undissolved}=100g-73g\\\\m_{undissolved}=27g

Best regards!

3 0
3 years ago
Which squirrel do you think is better suited for the environment, the gray one or the white one? and why
boyakko [2]

Answer:

The grey squirrel.

Explanation:

This is your answer because the white one would have a harder time to blend in with the tree's and the environment, whilst the grey one is better suited for its environment better due to the fact that it can blend in with the trees, and hide better.

3 0
3 years ago
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