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kiruha [24]
3 years ago
10

Yo please help I will give you 10 points PLEASE

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
6 0

Answer:

<h3>DEPENDENT VARIABLE</h3>

Explanation:

I HOPE IT HELPS :)

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A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is
erastova [34]

Answer: The total width of a crystal is 1.65 mm.

Explanation:

Horizontal length between the two molecules = 16.5 nm

Width of the 10^5 molecules :16.5 nm\times 10^5=16.5\times 10^5 nm

1 nm=10^{-6} mm

The total width of a crystal in millimeter=16.5\times 10^5\times 10^{-6} mm=1.65 mm

The total width of a crystal is 1.65 mm.

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3 years ago
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Which element would lose electrons during ionic bonding choose all that apply
yawa3891 [41]

Answer:

All of them!

Explanation:

Since Mg, Li, Ca, and Cs are all in groups 1 and 2 of the periodic table, they are alkali/alkaline earth metals and will all lose electrons during ionic bonding.

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3 years ago
How many electrons, protons, neutrons, and what is the atomic number and atomic mass (if any) does Fluoride have?
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Fluoride is an anion of Fluorine

What this means is that the two have the same number of protons (9), but Fluoride has 10 electrons compared to Fluorine's 9.

So the answers are:
Protons - 9
Neutrons - 9
Electrons - 10
Atomic Number - 9
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3 years ago
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What is the difference between a sea and an ocean
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Seas are smaller than oceans. Oceans are where land and water meet, and are usually bigger.

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5. What is the mass of 9.80 x 1023 formula units of zinc chlorate, Zn(CO3)2?
Zielflug [23.3K]

Answer:

\boxed{\text{378 g}}

Explanation:

We must convert formula units of Zn(ClO₃)₂ to moles and then to grams of Zn(ClO₃)₂.

Step 1. Convert formula units to moles

\text{Moles of Zn(ClO$_{3}$)$_{2}$}\\\\= 9.80 \times10^{23}\text{ formula units Zn(ClO$_{3}$)$_{2}$} \times \dfrac{\text{1 mol Zn(ClO$_{3}$)$_{2}$}}{6.022 \times\ 10^{23} \text{ formula units Zn(ClO$_{3}$)$_{2}$}}\\\\= \text{1.627 mol Zn(ClO$_{3}$)$_{2}$}

Step 2. Convert moles to grams

\text{Mass of Zn(ClO$_{3}$)$_{2}$}\\\\= \text{1.627 mol Zn(ClO$_{3}$)$_{2}$} \times \dfrac{\text{232.29 g Zn(ClO$_{3}$)$_{2}$}}{\text{1 mol Zn(ClO$_{3}$)$_{2}$}}\\\\= \text{378 g Zn(ClO$_{3}$)$_{2}$}\\\\\text{The mass of Zn(ClO$_{3}$)$_{2}$ is } \boxed{\textbf{378 g}}

5 0
3 years ago
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