<em>A</em><em> </em><em>time</em><em> </em><em>machine</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>device</em><em> </em><em>which </em><em>can</em><em> </em><em>transport </em><em>an</em><em> </em><em>object</em><em> </em><em>or</em><em> </em><em>person</em><em> </em><em>back</em><em> </em><em>in</em><em> </em><em>time</em><em> </em><em>or</em><em> </em><em>in</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>future</em><em>.</em><em> </em>
<em>Ali</em><em> </em><em>Razeghi</em><em> </em><em>is </em><em>the </em><em>person </em><em>who </em><em>invented</em><em> </em><em>the</em><em> </em><em>time</em><em> </em><em>machine</em><em>.</em>
Answer:
27 liters of hydrogen gas will be formed
Explanation:
Step 1: Data given
Number of moles C = 1.03 moles
Pressure H2 = 1.0 atm
Temperature = 319 K
Step 2: The balanced equation
C +H20 → CO + H2
Step 3: Calculate moles H2
For 1 mol C we need 1 mol H2O to produce 1 mol CO an 1 mol H2
For 1.03 moles C we'll have 1.03 moles H2
Step 4: Calculate volume H2
p*V = n*R*T
⇒with p = the pressure of the H2 gas = 1.0 atm
⇒with V = the volume of H2 gas = TO BE DETERMINED
⇒with n = the number of moles H2 gas = 1.03 moles
⇒with R = the gas constant = 0.08206 L*Atm/mol*K
⇒with T = the temperature = 319 K
V = (n*R*T)/p
V = (1.03 * 0.08206 *319) / 1
V = 27 L
27 liters of hydrogen gas will be formed
Answer:
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Answer:
THE VOLUME OF THE BALLOON IS 1.45 L
Explanation:
At sea level:
Volume = 2 L
Pressure = 1 atm
Temperature = 12 °C
At 30000 ft altitude:
Pressure = 0.30 atm
Temperature = -55°C
Volume = unknown
Using the general gas formula:
P1 V1 / T1 = P2 V2 / T2
Re-arranging the formula by making V2 the subject of the equation, we have;
V2 = P1 V1 T2 / T1 P2
V2 = 1 * 2 * 12 / 0.30 * 55
V2 = 24 / 16.5
V2 = 1.45 L
The volume of the balloon at the temperature of -55 C and 0.30 atm is 1.45 L
