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Lostsunrise [7]
3 years ago
13

A chef is going to use a mixture of two brands of italian dressing. the first brand contains 9% vinegar, and the second brand co

ntains 15% vinegar. the chef wants to make 330 milliliters of a dressing that is 11% vinegar. how much of each brand should she use?
Chemistry
1 answer:
AveGali [126]3 years ago
8 0
Call x the volume of first brand (9% vinegar) and y the volume of the second brand (15% vinegar).

1) Balance on vinegar content:

x*9% + y*15% = 330 * 11%

=> 9x + 15y = 3630     ---- Equation (1)


2) Balance on volume of dressing:

x + y = 330    ---- Equation (2)

3) Mulitply equation (2)

9x + 9y = 2970

4) subtract from equation (1)

=> 15y - 9y = 3630 - 2970

=> 6y = 660

=> y = 660 / 6

=> y = 110 ml

5) replace y value in the equation (2)

x + 110 = 330

=> x = 330 - 110

=> x = 220 ml.

Answer: he should use 220 ml of the first brand (9% vinegar) and 110ml of the second brand (15% vinegar).


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43 mg = [?]g <br>A. 0.043 g <br>B. 4.3 g <br>C. 4300 g <br>D. 43,000 g​
Ymorist [56]

Answer:

Option A (0.043 g) is the correct answer.

Explanation:

Given:

= 43 mg

As we know,

1 \ mg = \frac{1}{1000} \ g

then,

⇒ 43 \ mg = \frac{43}{1000}  \ g

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Thus, the above is the correct alternative.

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Explanation:

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How many grams of a 32.9% potassium sulfate solution would contain 181.6 g potassium
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Answer:

grams of solution = 551.98 g

Explanation:

Given data:

Percentage of solution = 32.9

Mass of solute = 181.6 g

Grams of solvent = ?

Solution:

Formula:

%  = [grams of solute / grams of solution] × 100

Now we will put the values in formula.

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