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4 years ago

7

Psychologists working from the humanistic perspective help people do all of the following except

1 answer:

mafiozo [28]4 years ago

8 0

Repress unwanted emotions

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An astronaut floating at rest in space throws a wrench in one direction and subsequently recoils back with a velocity in the opp

Jobisdone [24]

Answer:

a) ll and Ill only

Explanation:

Let the mass of the wrench = m

and the mass of the astronaut = M

Initially, the velocity of the astronaut and wrench are zero.

The astronaut throws the wrench in one direction and subsequently recoils back with a velocity in the opposite direction.

Let v and V be the velocity of the wrench and the velocity of the astronaut respectively.

In space, there is no external force acting, the momentum must be conserved.

So, m(0)+M(0)=m(v)+M(V)

So, 0=mv+MV

$\Rightarrow mv=-MV$ ...(i)

Here, the momentum of the wrench = mv, and the momentum of the astronaut= MV. The negative sign showing that both the momentum are in opposite direction.

Therefore, the momentum of the wrench is equal and opposite to the momentum of the astronaut.

According to Newton's second law, the rate of change of momentum = applied force.

Let it take $\Delta t$ seconds to change the momentum.

So, for the wrench

$m(v-0)/\Delta t= F_w \\\\\Rightarrow m(v-0)=F_w\Delta t \\\\\Rightarrow mv=F_w\Delta t \cdots(ii)$

Here, $F_w\Delta t$ is the impulse applied to the wrench.

Similarly, for the astronaut

$M(-V-0)/\Delta t= F_a$ [negative sign (-V) for opposite direction]

$\Rightarrow M(-V-0)=F_a\Delta t \\\\\Rightarrow -MV=F_a\Delta t$

Here, $F_a\Delta t$ is the impulse applied to the astronaut.

So, the impulse on the astronaut.

By using equations (i) and (ii)

$F_a\Delta t=F_w\Delta t$

Therefore, the impulse applied to the wrench is equal and opposite to the impulse applied to the astronaut.

Hence, option (a) is correct.

3 0

3 years ago

An ice sled powered by a rocket engine starts from rest on a large frozen lake and accelerates at 12.8 m/s2 . At t1 the rocket e

Simora [160]

Answer:4.39 s

Explanation:

Given

initial velocity $u=0$

acceleration $a=12.8 m/s^2$

velocity acquired by sled in $t_1$ time

$v=0+at$

$v=12.8t_1$

distance traveled by sled in $t_1 s$

$v^2-u^2=2as$

$(12.8t_1)^2-0=2\times 12.8\times s_1$

$s_1=6.4\cdot t_1^2$

distance traveled in $t_2$ time with velocity $v=12.8t_1$

$s_2=v\times t_2$

$s_2=12.8\times t_1\times t_2$

$s_2=12.8\cdot t_1\cdot t_2$

$s_1+s_2=5.37\times 10^3$

$6.4t_1^2+12.8t_1t_2=5370$ ----1

$t_1+t_2=97.7 s$

$t_2=97.7-t_1$

substitute the value of $t_2$ in 1

we get

$6.4t_1^2-1250.56t_1+5370=0$

thus $t_1=\frac{1250.56-1194.33}{12.8}=4.39 s$

$t_1=4.39 s$

5 0

4 years ago

If molecules in a substance move FASTER will the TEMPERATURE increase or decrease?

statuscvo [17]

The temperature will increase

4 0

4 years ago

A truck weighing 3.0 × 104

andreev551 [17]

Answer:

A truck weighing 3.0 × 104

newtons was driven up a

hill that is 1.6 × 103

meters long to a level area that

is 8.0 × 102

meters above the starting point. If the

trip took 480 seconds, what was the minimum power

required?

Explanation:

the answer is 1292.8

<u><em>brainliest plzzzzzzzzzzzzzzzzzzzzzz</em></u>

5 0

3 years ago

Suppose that the most massive car ever built is moving down a 10.00 slope when the driver applies the brakes. The net force acti

slava [35]

Hey there!

Use the question and search for a quizlet or science solving program

Here is a link:

www.scienceslovingprogram.com

Or

www.sciencehelp.com

6 0

3 years ago