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2 years ago

Convert 4.00 atm to mmHg

Chemistry

1 answer:

Ksivusya [100]2 years ago

3 0

Answer:

3040 mmHg

Explanation:

Here

we have to convert 4.00 atm to mmHg

As we know that

The number of atm in 1 mmHg is 0.0013157895567935

Now there is 4.00 atm So, in mmHg it would be

And, according to this, the working is given below:

= 4 ÷ 0.0013157895567935

= 3,039.99

= 3040 mmHg

Hence, the last option is correct

And, the same is relevant and considered too

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Cells are too small to see with the naked eye.

It's pretty straight forward, use the cross-out method.

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2) If the lenses of a microscope reduced the image of an organism to the size of a cell, you'd be seeing a very tiny human through your microscope, instead of actual cells.

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True or false. The greater the distance that the plane moves from an object, the lower the force that will be applied when the

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Answer:

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If you place 1.0 L of ethanol (C2H5OH) in a small laboratory that is 3.0 m long, 2.0 m wide, and 2.0 m high, will all the alcoho

ankoles [38]

If you place 1.0 L of ethanol (C2H5OH) in a small laboratory that is 3.0 m long, 2.0 m wide, and 2.0 m high, will all the alcohol evaporate? If some liquid remains, how much will there be? The vapor pressure of ethyl alcohol at 25 °C is 59 mm Hg, and the density of the liquid at this temperature is 0.785g/cm^3 .

will all the alcohol evaporate? or none at all?

Answer:

Yes, all the ethanol present in the laboratory will evaporate since the mole of ethanol present in vapor is greater. The volume of ethanol left will therefore be zero.

Explanation:

Given that:

The volume of alcohol which is placed in a small laboratory = 1.0 L

Vapor pressure of ethyl alcohol at 25 ° C = 59 mmHg

Converting 59 mmHg to atm ; since 1 atm = 760 mmHg;

Then, we have:

= $\frac{59}{760}atm$

= 0.078 atm

Temperature = 25 ° C

= ( 25 + 273 K)

= 298 K.

Density of the ethanol = 0.785 g/cm³

The volume of laboratory = l × b × h

= 3.0 m × 2.0 m × 2.5 m

= 15 m³

Converting the volume of laboratory to liter;

since 1 m³ = 100 L; Then, we have:

15 × 1000 = 15,000 L

Using ideal gas equation to determine the moles of ethanol in vapor phase; we have:

PV = nRT

Making n the subject of the formula; we have:

$n = \frac{PV}{RT}$

$n = \frac{0.078 * 15000}{0.082*290}$

n = 47. 88 mol of ethanol

Moles of ethanol in 1.0 L bottle can be calculated as follows:

Since numbers of moles = $\frac{mass}{molar mass}$

and mass = density × vollume

Then; we can say ;

number of moles = $\frac{density*volume }{molar mass of ethanol}$

number of moles = $\frac{0.785g/cm^3*1000cm^3}{46.07g/mol}$

number of moles = $\frac{&85}{46.07}$

number of moles = 17.039 mol

Thus , all the ethanol present in the laboratory will evaporate since the mole of ethanol present in vapor is greater. The volume of ethanol left will therefore be zero.

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3 years ago

Human reaction time is usually about 0.18 s. If your lab partner holds a ruler between your finger and thumb and releases it fro

Marizza181 [45]

Answer:

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Explanation:

From the question given above, the following data were obtained:

Time (t) = 0.18 s

Acceleration due to gravity (g) = –9.81 m/s²

Height (h) =?

We can obtain how far the ruler will fall by using the following equation:

H = ½gt²

H = ½ × –9.81 × 0.18²

H = ½ × –9.81 × 0.0324

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2 years ago

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Dennis_Churaev [7]

Answer:

Explanation:

We can determine the number of valence electrons of an element:

If it belongs to Groups 1 and 2, the number of valence electrons is equal to the number of group and the differential electron occupies the s subshell.

If it belongs to the groups 13-18, the number of valence electrons is equal to: "Number of group - 10" and the differential electron occupies the p subshell.

Which pair of elements have the same valence electronic configuration of np³?

(a) O and Se. NO. They belong to the group 16 and the valence electron configuration is ns² np⁴.

(b) Ge and Pb. NO. They belong to the group 14 and the valence electron configuration is ns² np².

(d) K and Mg. NO. They belong to the groups 1 and 2 and the valence electron configuration is ns¹ and ns².

(e) Al and Ga. NO. They belong to the group 13 and the valence electron configuration is ns² np¹.

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