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Marrrta [24]
3 years ago
7

Which product forms from the synthesis reaction between strontium (Sr) and sulfur (S)? O A. Sres O B. Srs O C. SS2 O D. Sr S2​

Chemistry
2 answers:
Morgarella [4.7K]3 years ago
7 0

Answer:

It should be Srs.

Explanation:

Sr + S is added to become (or basically chemically combined) SrS

nlexa [21]3 years ago
7 0

Answer:

SrS

Explanation:

Ap3x

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Answer:

62.50

Explanation:

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3 0
3 years ago
A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below. 2HCl
tensa zangetsu [6.8K]
The answer is D
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The density of mercury is 13.6 g/mL What is the mass in kilograms of 5L of mercury?
Oliga [24]

Answer:

68kg

Explanation:

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5 0
4 years ago
A chemist needs 500.0 mL of a 1.500 M perchloric acid solution. The stockroom provides the chemist with
Lynna [10]

Answer:-  47.62 mL

Solution:- It is a dilution problem where we are asked to calculate the volume of 15.75 M perchloric acid solution required to make 500.0 mL of 1.500 M solution.

For solving this type of problems we use the dilution equation:

M_1V_1=M_2V_2

Where, M_1 is the concentration of the concentrated solution and V_1 is it's volume.

M_2 is the concentration of the diluted solution and V_2 is it's volume.  Let's plug in the values in the equation and solve it for V_1 .

15.75M(V_1)=1.500M(500.0mL)

On rearranging this for V_1 :

V_1=\frac{1.500M(500.0mL)}{15.75M}

V_1=47.60mL

So, 47.62 mL of 15.75 M perchloric acid are required to make 500.0mL of 1.500 M solution.

3 0
4 years ago
You fill a balloon with helium gas to a volume of 2.68L at 23°C and 789mmHg. Then you release the balloon and it rises. What wil
wlad13 [49]

Answer : The final volume of balloon will be, 3.35 L

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P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = 789 mmHg

P_2 = final pressure = 632 mmHg

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Now put all the given values in the above equation, we get:

789mmHg\times 2.68L=632mmHg\times V_2

V_2=3.35L

Therefore, the final volume of balloon will be, 3.35 L

3 0
3 years ago
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