D. quantitative data can be recorded.
Answer:
Aromatic Hydrocarbons
Explanation:
Aromatic (Pleasant Odour) Hydrocarbons are those having pleasant odours.
Answer:
(a) The rate of formation of K2O is 0.12 M/s.
The rate of formation of N2 is also 0.12 M/s
(b) The rate of decomposition of KNO3 is 0.24 M/s
Explanation:
(a) From the equation of reaction, the mole ratio of K2O to O2 is 2:5.
Rate of formation of O2 is 0.3 M/s
Therefore, rate of formation of K2O = (2×0.3/5) = 0.12 M/s
Also from the equation of reaction, mole ratio of N2 to O2 is 2:5.
Rate of formation of N2 = (2×0.3/5) = 0.12 M/s
(b) From the equation of reaction, mole ratio of KNO3 to O2 is 4:5.
Therefore, rate of decomposition of KNO3 = (4×0.3/5) = 0.24 M/s
Answer is C.) G<span>oes from extremely cold to extremely hot during a lunar day </span>
The reason is because the temperatures on the moon<span> are very hot in the daytime, about 100 degrees C. At night, the </span>lunar <span>surface gets very cold, as cold as minus 173 degrees C. This wide variation is because Earth's </span>moon has no atmosphere to hold in heat at night or prevent the surface from getting so hot during the day.
Answer:
E = 4.78×10^−19 J
Explanation:
The chemical equation for the energy of a photon is given by:
E =hν , where h is the Planck constant and ν is the frequency.
E =hν = 6.626×10^−34 Js × 7.21×10^ 14
s−1 = 4.78 × 10^−19 J
