It is b, i learned this last year hope this helps
Answer:
There is 50.2 kJ heat need to heat 300 gram of water from 10° to 50°C
Explanation:
<u>Step 1: </u>Data given
mass of water = 300 grams
initial temperature = 10°C
final temperature = 50°C
Temperature rise = 50 °C - 10 °C = 40 °C
Specific heat capacity of water = 4.184 J/g °C
<u>Step 2:</u> Calculate the heat
Q = m*c*ΔT
Q = 300 grams * 4.184 J/g °C * (50°C - 10 °C)
Q = 50208 Joule = 50.2 kJ
There is 50.2 kJ heat need to heat 300 gram of water from 10° to 50°C
Answer: I think it's C
Explanation: I hope this helps (Sorry if it doesn't)
Answer:
732.0601 mmHg
Explanation:
Given data:
Pressure = 97.6 KPa
Given pressure in mmHg = ?
Solution:
Kilo pascal and millimeter mercury both are units of pressure.
Kilo pascal is denoted as "KPa"
Millimeter mercury is denoted as " mmHg"
Kilo pascal is measure of force per unit area while also define as newton per meter square.
It is manometric unit of pressure. It is the pressure generated by column of mercury one millimeter high.
Conversation of kilopascal to mmHg:
97.6 × 7.501 = 732.0601 mmHg
