An unknown gas has pressure, volume and temperature of 0.9 atm 8L and 120°C respectively. How many moles of gas are present?
1 answer:
Answer:
n = 0.223 mol.
Explanation:
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In this case, according to the given information, it is possible for us to approach this problem via the ideal gas law, which involves the pressure, moles, temperature and volume of the gas:
Thus, by solving for moles we obtain:
Therefore, we plug in the given volume, temperature (in Kelvins) and pressure to obtain:
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Answer:
Explanation:
In the chlorination of alkanes, the condition necessary is UV light so free radical substitution can take place. For alkanes like pentane, the primary, secondary and tertiary Hydrogen atoms (Hydrogen atoms bonded to their respective carbon) þare taken into consideration and this is because the tertiary Hydrogen is the most reactive (due to bond dissociation energy) hence the easiest to be substituted. The trend is as follows in the order of their reactivity;
1° < 2° < 3°
So, the products of the chlorination of pentane, the principal monochloride constituted is 3 - chloropentane while the other two monomers are:
2- chloropentane
1- chloropentane
Below is the attachment showing the structural formula of the three monochloride constituted pentane.
