An unknown gas has pressure, volume and temperature of 0.9 atm 8L and 120°C respectively. How many moles of gas are present?
1 answer:
Answer:
n = 0.223 mol.
Explanation:
Hello there!
In this case, according to the given information, it is possible for us to approach this problem via the ideal gas law, which involves the pressure, moles, temperature and volume of the gas:
Thus, by solving for moles we obtain:
Therefore, we plug in the given volume, temperature (in Kelvins) and pressure to obtain:
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The answer is 3.
<span>The relation between number of half-lives (n) and decimal amount remaining (x) can be expressed as:
</span>
We need to calculate n, but we need x to do that. To calculate what p<span>ercentage of a radioactive species would be found as daughter material, we must calculate what amount remained:
1.28 -</span> 1.12 = 0.16
If 1.28 is 100%, how much percent is 0.16:
1.28 : 100% = 0.16 : x
x = 12.5%
Presented as decimal amount:
x = 0.125
Now, let's implement this in the equation:
<span>
</span>
Because of the exponent, we will log both sides of the equation:
<span>
</span>
Therefore, 3 half-lives have passed <span> since the sample originally formed.</span>
<span>The relation between number of half-lives (n) and decimal amount remaining (x) can be expressed as:
</span>
We need to calculate n, but we need x to do that. To calculate what p<span>ercentage of a radioactive species would be found as daughter material, we must calculate what amount remained:
1.28 -</span> 1.12 = 0.16
If 1.28 is 100%, how much percent is 0.16:
1.28 : 100% = 0.16 : x
x = 12.5%
Presented as decimal amount:
x = 0.125
Now, let's implement this in the equation:
<span>
</span>
Because of the exponent, we will log both sides of the equation:
<span>
</span>
Therefore, 3 half-lives have passed <span> since the sample originally formed.</span>
Answer:
Concentration of A at equilibrium = 1 - 0.5 = 0.5 M
Explanation:
Equilibrium constant = 0.5
Initial concentration of A = 1 M
Initial 1 0 0
At equi. 1-x x x
Equilibrium constant =
on solving,
x = 0.5 M
Concentration of A at equilibrium = 1 - 0.5 = 0.5 M