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Ipatiy [6.2K]
2 years ago
8

If you want to make 8.00 moles of AlF₃ how many moles of F₂ will you need, using the following balanced chemical equation? 2 Al

+ 3 F₂ → 2 AlF₃
Chemistry
1 answer:
Zinaida [17]2 years ago
7 0

Answer:

You will need 12 moles of F2 if you want to make 8 moles of AlF3.

Explanation:

It takes 3 moles F2 to make 2 moles of AlF3 (this will be our mole ratio)

2 moles AlF3/3 moles F2 =8 moles AlF3/x moles AlF3.

x=12 moles AlF3

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Classify each of the following elements as
tino4ka555 [31]

Answer:Silicon is neither metal nor non-metal; it's a metalloid, an element that falls somewhere between the two. The category of metalloid is something of a gray area, with no firm definition of what fits the bill, but metalloids generally have properties of both metals and non-metals.

Explanation:

5 0
3 years ago
Read 2 more answers
In the chemical reaction:
velikii [3]

Taking into account the reaction stoichiometry and definition of limiting reactant, AgNO₃ will be the limiting reagent.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Cu + 2 AgNO₃  → 2 Ag + Cu(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Cu: 1 mole
  • AgNO₃: 2 moles
  • Ag: 2 moles
  • Cu(NO₃)₂: 1 mole

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Cu reacts with 2 moles of AgNO₃, 1.8 moles of Cu reacts with how many moles of AgNO₃?

amount of moles of AgNO_{3} =\frac{1.8 moles of Cux2 moles of AgNO_{3} }{1 mole of Cu}

<u><em>amount of moles of AgNO₃= 3.6 moles</em></u>

But 3.6 moles of AgNO₃ are not available, 2 moles are available. Since you have less moles than you need to react with 1.8 moles of Cu, AgNO₃ will be the limiting reagent.

<h3>Summary</h3>

In summary, AgNO₃ will be the limiting reagent.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

8 0
1 year ago
How much Sr(OH)2 • 8 H2O (M = 265.76) is needed to prepare 250.0 ML of solution in which [OH]= 0.100M?
SVEN [57.7K]
Use the formula 
first step: 
Use the formula 
molarity= mole/liter
change ml to l
plug in data
 to get .1=mole/.25 or .1M*.25liter
which =.025 moles
then divide .025 moles by two because there are two OH in Sr(OH)2 
then multiply that by 265.76 (the molar mass of water) 
.0125*265.76
which is 3.32grams this is your answer 




6 0
3 years ago
Read 2 more answers
What is an Atom? please help
JulsSmile [24]

Answer:

An atom is the basic building block of matter. Anything that has a mass-- in other words, anything that occupies space--is composed of atoms.

5 0
3 years ago
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If I have 7.5 L of a gas in a piston at a pressure of 1.75 atm and compress the gas until its volume is 3.7 L, what will the new
Sergio [31]

Answer:

3.55atm

Explanation:

We will apply Boyle's law formula in solving this problem.

P1V1 = P2V2

And with values given in the question

P1=initial pressure of gas = 1.75atm

V1=initial volume of gas =7.5L

P2=final pressure of gas inside new piston in atm

V2=final volume of gas = 3.7L

We need to find the final pressure

From the equation, P1V1 = P2V2,

We make P2 subject

P2 = (P1V1) / V2

P2 = (1.75×7.5)/3.7

P2=3.55atm

Therefore, the new pressure inside the piston is 3.55atm

7 0
3 years ago
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