Why do real gases deviate from gas laws

Naturally occuring element X exists in three isotopic forms: X-28 (27.730 amu, 60.58% abundance), X-29 (28.841 amu, 18.35% abund

bazaltina [42]

The Average atomic weight of X is 28.7amu

Isotopes are atoms with the same number of protons but differing numbers of neutrons.

Different isotopes have various atomic masses.

The proportion of atoms with a particular atomic mass that can be found in a naturally occurring sample of an element is known as the relative abundance of an isotope.

An element's average atomic mass is computed as a weighted average by multiplying the relative abundances of its isotopes by their respective atomic masses, then adding the resulting products.

Using mass spectrometry, it is possible to determine the relative abundance of each isotope.

The atomic weight of the element will be a weighted average of the isotopes based on the relative abundance:

(27.730 x 0.6058) + (28.841 x 0.1835) + (31.321 x 0.2107) = 16.7988 + 5.2923+ 6.599 = 28.690 = 28.7 amu.

Average atomic weight of X is 28.7amu

Learn more about Average Atomic Weight here

brainly.com/question/6200158

#SPJ4

3 0

2 years ago

Identify the type of plant tissue that brings in gases:

artcher [175]

Answer:

epidermal

Explanation:

6 0

3 years ago

Read 2 more answers

identify the reagents necessary to achieve each of the following transformations o3 dms, pcc, ch2cl, h2so4,h2o,hgso4

hoa [83]

the reagents necessary to convert alcohol to ketone $Na_2Cr_2O_7 , H_2O$ which involves oxidation of alcohols.

<h3>What is oxidation of alcohols?</h3>

Alcohol oxidation is a significant organic chemistry process. Secondary alcohols can be oxidized to produce ketones, while primary alcohols can be oxidized to produce aldehydes and carboxylic acids.
In contrast, tertiary alcohols cannot be oxidized without the C-C bonds in the molecule being broken.
In order to cause primary alcohols to oxidize into aldehydes

$Cr_2O_7 ^-^2$ (dichromate)
$CrO_3$ /pyridine (Collins reagent)
Chromium pyridinium compound (PCC)
Dichromate of pyridinium (PDC, Cornforth reagent)
Periodinane by Dess-Martin
Oxalyl chloride with dimethylsulfoxide (DMSO) for Swern

oxidation of secondary alcohols to ketones

$Cr_2O_7 ^-^2$ (dichromate)
$CrO_3$ /pyridine (Collins reagent)
Chromium pyridinium compound (PCC)
Dichromate of pyridinium (PDC, Cornforth reagent)
Periodinane by Dess-Martin
Oxalyl chloride and dimethyl sulfoxide (DMSO) (Swern oxidation)
$CrO_3, H_2SO_4$ /acetone (Jones oxidation)
Acetone with aluminum isopropoxide (Oppenauer oxidation)

To learn more about oxidation of alcohols with the given link

brainly.com/question/7207863

#SPJ4

<u>Question:</u>

Identify the reagents necessary to achieve each of the following transformations

$a. O_3 , DMS$

$b.H_2SO_4 , H_2O , HgSO_4$

$c.Na_2Cr_2O_7 , H_2O$

$d.Fe ^ {2+}, NaOH$

3 0

2 years ago

Calculate the percentage by mass of chlorine in Cobalt (II) chloride (cocl2)

Likurg_2 [28]

Explanation:

Divide the mass of chlorine by the molar mass of cobalt chloride, then multiply by 100.

Molar Mass of Cobalt Chloride.

Mass of Chlorine in Cobalt Chloride.

Percent Composition of Chlorine.

8 0

3 years ago

Read 2 more answers

When the equation Sn + HNO₃ → SnO₂ + NO₂ + H₂O is balanced in acidic solution, what is the smallest whole-number coefficient for

balu736 [363]

Answer:

1.

Explanation:

Hello,

In this case, for the given reaction we first assign the oxidation state for each species:

$Sn^0 + H^+N^{5+}O^{-2}_3 \rightarrow Sn^{4+}O_2 + N^{4+}O^{2-}_2 + H^+_2O^-$

Whereas the half reactions are:

$Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-\\\\H^++H^+N^{5+}O^{-2}_3 +1e^-\rightarrow N^{4+}O^{2-}_2+H_2O$

Next, we exchange the transferred electrons:

$1\times(Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-)\\\\4\times (H^++H^+N^{5+}O^{-2}_3 +1e^-\rightarrow N^{4+}O^{2-}_2+H_2O)\\\\\\Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-\\\\4H^++4H^+N^{5+}O^{-2}_3 +4e^-\rightarrow 4N^{4+}O^{2-}_2+4H_2O$

Afterwards, we add them to obtain:

$Sn^0+2H_2O+4H^++4H^+N^{5+}O^{-2}_3 \rightarrow Sn^{4+}O_2 +4H^++4N^{4+}O^{2-}_2+4H_2O$

By adding and subtracting common terms we obtain:

$Sn^0+4H^+N^{5+}O^{-2}_3 \rightarrow Sn^{4+}O_2 +4N^{4+}O^{2-}_2+2H_2O$

Finally, by removing the oxidation states we have:

$Sn + 4HNO_3 \rightarrow SnO_2 + 4NO_2 + 2H_2O$

Therefore, the smallest whole-number coefficient for Sn is 1.

Regards.

6 0

3 years ago