Subtract. (8u - 2v + 7w) and (5u + v + 6w)

Find the area of 14 nine and eight

Reptile [31]

Answer:

Can u add the pic and I’ll answer it

Step-by-step explanation:

3 0

3 years ago

I´m out of points only 50 left here have it :(

klio [65]

Answer:

thank youuuuuuu :)

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

The total amounts of rainfall at various points in time during a thunderstorm are shown in the table. Rainfall During a Thunders

beks73 [17]

Answer:

C. y almost-equals 0.59 x + 0.03

Step-by-step explanation:

The linear regression equation is y ≈ 0.594 x + 0.029; r ≈ 0.998.

0.594 must be rounded down to 0.59 (digits finished in 1, 2, 3 and 4 are rounded down)

0.029 must be rounded up to 0.03 (digits finished in 5, 6, 7, 8 and 9 are rounded up)

5 0

3 years ago

Read 2 more answers

In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent (Pew Research, June 5, 2014). An independe

enot [183]

Answer:

a)

$n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2$ , in which z is related to the confidence level.

b) A sample size of 991 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent

This means that $\pi = 0.16$

a. What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.03 (round up to the next whole number).

This is n for which $M = 0.03$ . So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = z\sqrt{\frac{0.16*0.84}{n}}$

$0.03\sqrt{n} = z\sqrt{0.16*0.84}$

$\sqrt{n} = \frac{z\sqrt{0.16*0.84}}{0.03}$

$(\sqrt{n})^2 = (\frac{z\sqrt{0.16*0.84}}{0.03})^2$

$n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2$ , in which z is related to the confidence level.

Question b:

99% confidence level,

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

$n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2$

$n = (\frac{2.575\sqrt{0.16*0.84}}{0.03})^2$

$n = 990.2$

Rounding up

A sample size of 991 is needed.

8 0

3 years ago

Find X and Y please explain

Alex777 [14]

In this diagram we see that 80 and 3x+4y are both vertical angles and vertical angles are congruent or always equal so we can set those two equations equal to each other then we can see that a line splits two angles making them supplementary (they equal 180 degrees) So we can have another equation, the two equations are:

3x+4y=80 and 3x+4y+7x-8y=180 (add like terms to simplify and get 10x-4y=180

Then use elimination to get rid of the y variables

10x-4y=180 (plus)

+3x+4y=80 (the negative 4 and positive 4 cancels each other out so you are left with:)

13x=160 (divide by x)

x=12.30769 which can be rounded to x=12.31

Then we have to plug in x into the first equation:

3(12.31) + 4y = 80

36.93 + 4y = 80 (subtract 36.93 from 80)

4y = 43.07 (divide)

y=10.7675 or rounded to 10.77

so x=12.31 and y=10.77

5 0

3 years ago