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KengaRu [80]
1 year ago
15

The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed?(a) 16(b

) 8(c) 4 (d) 2(e) 1
Physics
1 answer:
maw [93]1 year ago
4 0

The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed: 2.

<h3>What is kinetic energy?</h3>
  • A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force.
  • Kinetic energy comes in five forms: radiant, thermal, acoustic, electrical, and mechanical.
  • The energy of a body in motion, or kinetic energy (KE), is essentially the energy of all moving objects. Along with potential energy, which is the stored energy present in objects at rest, it is one of the two primary types of energy.
  • Explain that a moving object's mass and speed are two factors that impact the amount of kinetic energy it will possess.

The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed: 2.

To learn more about kinetic energy, refer to:

brainly.com/question/25959744

#SPJ4

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An 11,000-watt radio station transmits at 880 kHz. Calculate the energy of a single photon at the transmitted frequency.
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The energy of a single photon at the transmitted frequency is \bold{5834.4 \times 10^{-31} \mathrm{J}}

Answer: Option b

<u>Solution:</u>

Energy of photon is given as E=\frac{h c}{\lambda}

Where  c is the velocity of Light \left(3 \times 10^{8} m / s\right)

h is planck's constant  \left(6.63 \times 10^{-34}\right)

λ is the wavelength of photon  

Energy of photon can be rewritten as E=h \times f

Where f is the frequency of photon  

Frequency of photon is obtained by dividing velocity of light by wavelength of photon.

f=\frac{c}{\lambda}

E=6.63 \times 10^{-34} \times 880 \times 10^{3}=5834.4 \times 10^{-31} \mathrm{J}

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Answer:

F=4673.95lbs

Explanation:

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F=\int\limits {p} \, dA

F=\int\limits^8_2 {pgx*\frac{7}{4}*(8-x)} \, dx

F=\int\limits^8_2 {62.5*\frac{7}{4}*x*(8-x)} \, dx

F=109.375\int\limits^8_4{(8x-x^2)} \, dx

F=109.375[4x^2-\frac{1}{3}x^3]|4,8

F=109.375*42.73=4673.95lbs

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