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KengaRu [80]
1 year ago
15

The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed?(a) 16(b

) 8(c) 4 (d) 2(e) 1
Physics
1 answer:
maw [93]1 year ago
4 0

The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed: 2.

<h3>What is kinetic energy?</h3>
  • A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force.
  • Kinetic energy comes in five forms: radiant, thermal, acoustic, electrical, and mechanical.
  • The energy of a body in motion, or kinetic energy (KE), is essentially the energy of all moving objects. Along with potential energy, which is the stored energy present in objects at rest, it is one of the two primary types of energy.
  • Explain that a moving object's mass and speed are two factors that impact the amount of kinetic energy it will possess.

The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed: 2.

To learn more about kinetic energy, refer to:

brainly.com/question/25959744

#SPJ4

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Here are 5:

Distance from source to receiver

Wind speed and direction

Wind gradients

Temperature gradients

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and there are many more...

Hope that was helpful.Thank you!!!

7 0
3 years ago
What’s 4.5 inches into centimeters?
marshall27 [118]

Answer:

11.43 cm

Explanation:

yes

3 0
3 years ago
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Two long wires hang vertically. wire 1 carries an upward current of 1.60
charle [14.2K]
3.00 is my correct answer this is what my teacher told me.thanks
7 0
3 years ago
An electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric
8090 [49]

Answer:

1.) 11 km/s

2.) 9.03 × 10^-5 metres

Explanation:

Given that an electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C.

Electron q = 1.6×10^-19 C

Electron mass = 9.11×10^-31 Kg

(a) What is the speed of the electron 1.3 ns after entering this region?

E = F/q

F = Eq

Ma = Eq

M × V/t = Eq

Substitute all the parameters into the formula

9.11×10^-31 × V/1.3×10^-9 = 48 × 1.6×10^-19

V = 7.68×10^-18 /7.0×10^-22

V = 10971.43 m/s

V = 11 Km/s approximately

(b) How far does the electron travel during the 1.3 ns interval?

The initial velocity U = 64 km/s

S = ut + 1/2at^2

S = 64000×1.3×10^-6 + 1/2 × 8.4×10^12 × ( 1.3×10^-9)^2

S =8.32×10^-5 + 7.13×10^-6

S = 9.03 × 10^-5 metres

3 0
2 years ago
A hydraulic lift has two connected pistons with cross-sectional areas 15 cm2 and 670 cm2. It is filled with oil of density 510 k
BigorU [14]

Answer:

Explanation:

Given

Cross-sectional area of two areas is

A_1=15\ cm^2

A_2=670\ cm^2

It is filled with oil of density \rho _0=510\ kg/m^3

mass of car place on Large area M=1100\ kg

Suppose a mass of m kg is placed on smaller area

According to pascal law's intensity of pressure is same at every point on Liquid

P_1=P_2

\frac{F_1}{A_1}=\frac{F_2}{A_2}

\frac{mg}{15}=\frac{Mg}{670}

m=1100\times \frac{15}{670}

m=24.62\ kg                            

4 0
3 years ago
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